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Eva8 [605]
2 years ago
13

In planning his report, byron breaks the major investigative problem into subproblems. this process is sometimes called ________

.
Chemistry
1 answer:
Delvig [45]2 years ago
4 0

In planning his report, Byron breaks the major investigative problem into subproblems. This process is sometimes called Factoring the problem.

<h3>What is meant by Factoring Problem?</h3>

Factorization can also refer to a broader breakdown of a mathematical entity into its component parts, which are smaller or simpler. For instance, each function might be included in the mix of an injective function and a subjective function. Matrix factorizations can take many different forms in matrices.

A matrix formulation of Gaussian elimination, for instance, has a unique LUP factorization for each matrix, which is the product of a lower triangular matrix L with all diagonal entries equal to one, an upper triangular matrix U, and a permutation matrix P.

Learn more about Factors with the help of the given link:

brainly.com/question/1921890

#SPJ4



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9. Given the following reaction:CO (g) + 2 H2(g) CH3OH (g)In an experiment, 0.45 mol of CO and 0.57 mol of H2 were placed in a 1
WITCHER [35]

Answer:

Keq=11.5

Explanation:

Hello,

In this case, for the given reaction at equilibrium:

CO (g) + 2 H_2(g) \rightleftharpoons CH_3OH (g)

We can write the law of mass action as:

Keq=\frac{[CH_3OH]}{[CO][H_2]^2}

That in terms of the change x due to the reaction extent we can write:

Keq=\frac{x}{([CO]_0-x)([H_2]_0-2x)^2}

Nevertheless, for the carbon monoxide, we can directly compute x as shown below:

[CO]_0=\frac{0.45mol}{1.00L}=0.45M\\

[H_2]_0=\frac{0.57mol}{1.00L}=0.57M\\

[CO]_{eq}=\frac{0.28mol}{1.00L}=0.28M\\

x=[CO]_0-[CO]_{eq}=0.45M-0.28M=0.17M

Finally, we can compute the equilibrium constant:

Keq=\frac{0.17M}{(0.45M-0.17M)(0.57M-2*0.17M)^2}\\\\Keq=11.5

Best regards.

3 0
4 years ago
As sample of gas occupies 2.00L with 5.00 moles present. What would happen to the volume if the number of moles is increased to
maw [93]
The volume would increase and it will become 4.00 L
8 0
3 years ago
How many grams are there in 3.34 mol HCl?
just olya [345]

Answer:

121.78 g

Explanation:

You multiply the mols by the grams in one mol.

4 0
3 years ago
1. Calculate the molarity of a sugar solution if 4 liters of the solution contains 8 moles of sugar
klio [65]

Answer:

The molarity of a sugar solution is 2 M.

Explanation:

Molarity is a concentration measure that expresses the moles of solute per liter of solution. In this case it is calculated with the simple rule of three:

4 L of solution--------8 moles of sugar

1 L of solution ------x= (1 L of solution x 8 moles of sugar)/4 L of solution

x=2 moles of sugar---> <em>The solution is 2M</em>

8 0
3 years ago
The reference point in motion is:
lyudmila [28]

Answer: the focal point

8 0
3 years ago
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