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8_murik_8 [283]
2 years ago
13

Galena, a mineral of lead, is a compound of the metal with sulfur. Analysis shows that a 2.34-g sample of galena contains 2.03 g

of lead. Calculate the:
(a) mass of sulfur in the sample;
Chemistry
1 answer:
dolphi86 [110]2 years ago
7 0

The mass of sulfur in the sample is 0.31g

To calculate mass of sulfur in sample: given that amount galena is 2.34g and mass of lead is 2.03 g as galena contain both lead and sulfur the mass of sulfur = mass of galena- mass of lead , that is, 2.34- 2.03=0.31g.The molecular mass is a algebraic sum of atomic mass of each element in the compound thus the mass of the compound can be obtained by adding atomic of each element. Lead(II) sulphide occurs naturally as the mineral galena, often known as lead glance (PbS). It is a significant source of silver and the most significant lead ore.

To learn more about mass:

brainly.com/question/19694949

#SPJ4

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A pipe leaks water at a rate of 1.24 mL/s. What is the rate of the water leak in L/hr?
Umnica [9.8K]

Answer:

b)4.46 L/hr

Explanation:

To solve this question we need to convert the mL to liters (Using the conversion of 1000mL = 1L) and convert the time from seconds to hours (3600s = 1hr)

<em>mL to L:</em>

1.24mL/s * (1L / 1000mL) = 0.00124L/s

<em>seconds to hours:</em>

0.00124L/s * (3600s / 1hr) = 4.46L/hr

Right answer is:

<h3>b)4.46 L/hr </h3>

3 0
3 years ago
600.0 mL of air is at 20.0 c what is the volume at 60.0
pogonyaev

682mL

Explanation:

Given parameters:

Initial volume of air = 600mL

Initial temperature = 20°C

Final temperature = 60°C

Unknown:

Final volume = ?

Solution:

To solve this problem, we apply Charles's law';

Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "

Mathematically;

   \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

V₁ is the initial volume  of air

T₁ is the initial temperature  of air

V₂ is the final volume  of air

T₂ is the final temperature of air

To proceed in solving this problem, we need to convert the given temperature to Kelvin;

T K = 273 + T°C

T₁  = 273 + 20 = 293K

T₂ = 273 + 60 = 333K

now input the parameters;

V_{2}  = \frac{V_{1} }{T_{1} }  x T_{2}  = \frac{600}{293 }  x 333

 V₂ = 682mL

learn more:

Gas laws brainly.com/question/2438000

#learnwithBrainly

 

8 0
3 years ago
Which choice tells how energy is transferred between the atmosphere and hydrosphere? runoff and condensation precipitation and e
4vir4ik [10]

Answer:

correct answer is  precipitation and evaporation

Explanation:

solution

correct answer is  precipitation and evaporation  because in the evaporation process of water cycle, the atmosphere is directly interact with the hydrosphere as water changes from liquid into vapor or  gas form

and Precipitation is the process when water that may be in the form of snow or hail or rain etc that is fall from the cloud into the open sky

so correct answer is  precipitation and evaporation

8 0
4 years ago
Read 2 more answers
If Mary likes Johnny, but Johnny likes Katie, and Katie likes Mary. What do they do?
RUDIKE [14]

Answer:

love triangle?- orr they can figure something out

8 0
3 years ago
Read 2 more answers
Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded co
shusha [124]

This question is an incomplete question, here is a complete question.

Perform the following calculation. Report the answer using the proper number of significant figures.

\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}=?

Answer : The answer will be, 3.46J/g.K

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

The given expression is,

\frac{1.012\times 10^{-3}J}{(0.025456g)\times (298.3682-298.3567)K}

\frac{1.012\times 10^{-3}J}{(0.025456g)\times (0.0115)K}

\Rightarrow 3.4569J/g.K

In the given expression, 1.012 has 4 significant figures, 0.025456 has 5 significant figures and 0.0115 has 3 significant figures. From this we conclude that 3 is the least significant figures in this problem. So, the answer should be in 3 significant figures.

Thus, the answer will be 3.46J/g.K

7 0
3 years ago
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