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Phoenix [80]
3 years ago
7

I need help with the last two questions please help quickly!!

Chemistry
1 answer:
Talja [164]3 years ago
6 0

Not sure about the last one, but I think the percent composition of zinc would be ~ 42.8232

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Which requires more energy to move an electron?
Mandarinka [93]

Answer:

From n=1 to n=2

Explanation:

Electrons in n=1 are strongly attracted to the nucleus and therefore will require great force to overcome the electrostatic force of attraction to displace them from the energy level to another.

The electrostatic force reduces as you progress to the outer energy levels.

4 0
3 years ago
Read 2 more answers
Which coefficients correctly balance the formula equation nh4no2(s)-> n2(g) + h2o(l)?
horrorfan [7]
NH4NO2 > N2 + 2 H2O
8 0
3 years ago
If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density
ankoles [38]

Answer:

The length of the wire = 352.66 feet.

Explanation:

A copper refinery produces a copper ingot weighing 150 lb. If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density of copper is 8.94 g/cm3. (Assume that the wire is a cylinder whose volume is V = πr2h, where r is the radius and h is its height or length.)

Step 1: Convert lb to kg

150 lb = 68.0389 kg

Step 2: Calculate volume of copper

Volume = mass / density

Volume = 68038.9 grams / 8.94 g/cm³

Volume = 7610.6 cm³ Cu

Step 3: Calculate length of wire

The diameter of the wire is 9.50 mm, so the radius is half of that (4.75 mm), or 0.475 cm.

The total "volume" of the wire is πr²h = (π)*(0.475 cm)²(h) = 0.708h = 7610 cm^3

7610 = 0.708h

h = 10749 cm = length of wire

The length of the wire = 352.66 feet.

7 0
3 years ago
Calculate the number of formula units in 2.50 mol NaNO
marta [7]

The number of formula units in 2.50 mol of the compound is  15.1 * 10^23.

The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.

6.02 * 10^23 formula units of the compound are contained in 1 mole

x formula units are contained in 2.5 moles of the compound

x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole

x = 15.1 * 10^23 formula units of the compound.

Learn more; brainly.com/question/9743981

3 0
2 years ago
Student carries out a titration to determine the concentration of a solution of
Nimfa-mama [501]

The concentration of the Nitric acid solution : 0.114 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Titrations can be acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases  

Reaction

HNO₃ + NaOH → NaNO₃ + H₂O​

Concentration a standard solution  of sodium hydroxide :  0.0998 mol/dm³ , and the volume = 25 cm³

moles NaOH=

\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles

<em>From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=</em><em>2.495 mlmoles</em>

<em></em>

The volume of HNO₃ = 21.8 cm³, so the concentration :

\tt M=\dfrac{n}{V}\\\\M=\dfrac{2.495}{21.8}\\\\M=0.114

7 0
3 years ago
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