The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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15 divided by 6 2/3 is 2 1/4
Answer:
2244 cm
Step-by-step explanation:
The first first thing we must do is find the LCM of the following numbers
(51; 68) = 204.
This means that the first time they coincide is at 204.
Now, since his steps always coincide after 204
In Nick's case
Nick's 204 ÷ 51 = 4th step
and in the case of the father
204 ÷ 68 of his father = 3rd step.
Which means that in the 204 cm distance, there will be a total of 6 foot steps, except in the first 204 cm when your "initial" step is counted.
Replacing these values we have that the total distance will be:
67-1 (initial step) / (6 * 204) = 2244 cm
Answer:
B. AAS Congruence Theorem
Step-by-step explanation:
Previous steps showed congruence of a side of the designated triangle, and two angles that do not bracket that side. In short form, you have shown congruence of ...
Angle - Angle - Side
so the AAS congruence theorem applies.
The answer to your equation is 1008