Set up the following equation for this segment:
x is segment AB's length, and 3x is segment BC's length. 20 is segment AC's length.
Combine like terms:
Divide both sides by 4 to get x by itself:
x will equal 5.
Plug this value into the values for both segments:
Segment AB:
Segment AB is 5 inches long.
Segment BC:
Segment BC is 15 inches long.
Answer:
x^4 -53x^2 +108x +160
Step-by-step explanation:
If <em>a</em> is a zero, then (<em>x-a</em>) is a factor. For the given zeros, the factors are ...
p(x) = (x +8)(x +1)(x -4)(x -5)
Multiplying these out gives the polynomial in standard form.
= (x^2 +9x +8)(x^2 -9x +20)
We note that these factors have a sum and difference with the same pair of values, x^2 and 9x. We can use the special form for the product of these to simplify our working out.
= (x^2 +9x)(x^2 -9x) +20(x^2 +9x) +8(x^2 -9x) +8(20)
= x^4 -81x^2 +20x^2 +180x +8x^2 -72x +160
p(x) = x^4 -53x^2 +108x +160
_____
The graph shows this polynomial has the required zeros.
Answer:
[rad] 2.41
Step-by-step explanation:
Since it gave you the point and the angle to find, you simply just have to solve for the inverse of cot. Remember cot is the opposite of tan, so cot is cos/sin. In that case, we plug into the calc (in radians):
cot^-1(-√5/2)
And we should get 2.41 as our answer!
Well, if the the triangle is rotated clockwise it will lie in quadrant 4. if it is rotated anticlockwise it will lie on quadrant 2
hope this helps
