The required equation of line B is 2y+5x=-2
The equation of a line in point-slope form is expressed as:
y-y0 = m(x-x0)
m is the slope of the line
(x0, y0) is the point on the line
Given the line A expressed as:
2x = 5y – 25
Rewrite in standard form
5y = 2x + 25
y = 2/5 x + 5
The slope will be 2/5
The slope of the perpendicular line will be;
![M = \frac{-1}{(2/5)}\\M = \frac{-5}{2}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B-1%7D%7B%282%2F5%29%7D%5C%5CM%20%3D%20%5Cfrac%7B-5%7D%7B2%7D)
Substitute the point (-6, 14) and slope -5/2 into the equation above to get the required equation of line B
![y-14=-5/2(x+6)\\2(y-14) = -5(x+6)\\2y-28=-5x-30\\2y+5x=-30+28\\2y+5x=-2\\](https://tex.z-dn.net/?f=y-14%3D-5%2F2%28x%2B6%29%5C%5C2%28y-14%29%20%3D%20-5%28x%2B6%29%5C%5C2y-28%3D-5x-30%5C%5C2y%2B5x%3D-30%2B28%5C%5C2y%2B5x%3D-2%5C%5C)
Hence the required equation of line B is 2y+5x=-2
Learn more here: brainly.com/question/13140886
Answer:
80 mg
Step-by-step explanation:
By proportion the daily allowance is 200 * 100/250
= 200 * 10/25
= 80 mg
Answer:
the answer is 25
Step-by-step explanation:
you subtract 25 from 100 you get 75 and when you subtract 25 from 75 you get 25
q<13
Step-by-step explanation:
2q is less than 26 so 1q has to be less than half of 26 or 13.
q<13