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Bumek [7]
2 years ago
6

4 .3 is V = πr³, wh 3 what is the formula in terms of r? please help

Mathematics
1 answer:
MakcuM [25]2 years ago
3 0

The rearranged formula for volume in terms of radius,r is  \sqrt[3]{\frac{V}{\pi } }.

What is volume?

  • Volume is a measure of enthralled three-dimensional space.
  • It's frequently quantified numerically using SI-deduced units or by colorful Homeric units( similar to the gallon, quart, boxy inch).
  • The description of length( cubed) is interrelated with volume. The volume of a vessel is generally understood to be the capacity of the vessel; i.e., the quantum of fluid( gas or liquid) that the vessel could hold, rather than the quantum of space the vessel itself displaces.
  • In ancient times, volume is measured using analogous-structured natural holders and latterly on, standardized holders.
  • Some simple three-dimensional shapes can have their volume fluently calculated using computation formulas.
  • Volumes of more complicated shapes can be calculated with integral math if a formula exists for the shape's boundary.

Volume, V = \pi r^3

Rearranging,

r =\sqrt[3]{\frac{V}{\pi } }

The rearranged formula for volume in terms of radius,r is  \sqrt[3]{\frac{V}{\pi } }.

Learn more about volume here:

brainly.com/question/1972490

#SPJ9

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

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D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

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Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

BC=\sqrt{(-35)^{2}}

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}

AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

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