Y = 1/2x + 6 Y = -2x + 3 Y= 1/2x + 3 Y= -1/2x + 3

Mathematics

2 answers:

TEA [102]3 years ago

7 0

Answer:

y=-1/2x+3

Step-by-step explanation:

it has a negative slope and it's not that steep which is why the slope isnt 2. also the first one is wrong because the y-intercept is 3

Irina18 [472]3 years ago

5 0

It is -1/2x+3 KSJSMSMSMS,MSMS,DD

You might be interested in

Please answer correctly and no links

victus00 [196]

Answer:

step 3

Step-by-step explanation:

take away 2 add 4 then multiple 9000 then divide 1 then you got your answer 20/56.

8 0

3 years ago

In a class of 40 students, 30 read

DIA [1.3K]

Ok so 24 of them and that would be ur answer

6 0

3 years ago

Round 721295.198715 to the nearest ten.

zimovet [89]

Answer:

7212960

Step-by-step explanation:

You have to round up since the number in the ones place is a 5.

4 0

3 years ago

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$