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bogdanovich [222]
3 years ago
10

Solve for b2 in A=1/2 h(b1+b2), if A=16, h=4, and b1=3

Mathematics
1 answer:
icang [17]3 years ago
4 0

Answer:

b_{2} = 5

Step-by-step explanation:

Substitute the given values into the formula

16 = \frac{1}{2} × 4(3 + b_{2})

16 = 2(3 + b_{2}) ( divide both sides by 2 )

8 = 3 + b_{2} ( subtract 3 from both sides )

5 = b_{2}


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A rectangular roof shingle has a perimeter of 32 inches and an area of 60 square inches. What are the dimensions of the shingle?
Lady bird [3.3K]

Answer:

Length = 6 inches, Width = 10 inches

Step-by-step explanation:

A rectangular roof shingle has a perimeter of 32 inches and an area of 60 square inches. What are the dimensions of the shingle?

Note :

L = Length

W = Width

The perimeter of a rectangle = 2( L + W)

The area of a rectangle = LW.

A rectangular roof shingle has a perimeter of 32 inches and an area of 60 square inches.

32 = 2( L + W)

Divide both sides by 2

16 = L + W.... Equation 1

L = 16 - W

Also:

LW = 60....... Equation 2

Let us substitute 16 - W for L in Equation 2

(16 - W)W = 60

16W - W² = 60

W² - 16W + 60 = 0

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Solving for L

W = 10

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