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bogdanovich [222]

3 years ago

10

Solve for b2 in A=1/2 h(b1+b2), if A=16, h=4, and b1=3

1 answer:

icang [17]3 years ago

4 0

Answer:

$b_{2}$ = 5

Step-by-step explanation:

Substitute the given values into the formula

16 = $\frac{1}{2}$ × 4(3 + $b_{2}$ )

16 = 2(3 + $b_{2}$ ) ( divide both sides by 2 )

8 = 3 + $b_{2}$ ( subtract 3 from both sides )

5 = $b_{2}$

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How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and

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Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

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Now, by substituting the above considerations in the above equation, we get:

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where,

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n = 20

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Answer :

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