<h2>
Answer:</h2>
is 3 ohms
<h2>
Step-by-step explanation:</h2>
In a circuit containing two resistors
and
connected together in parallel, the total resistance
is given by;
---------(i)
<em>Make </em>
<em> subject of the formula;</em>
=>
=> 
=>
---------------(ii)
From the question,
= 6Ω
= 2Ω
Substitute these values into equation (ii) as follows;
=> 

= 3Ω
Therefore, the value of
= 3 ohms or
= 3Ω
Answer: 195
Step-by-step explanation:
Cost per student = $4
Total number who attended = n
The cost of the total of student who attended will be cost per student multiplied by the total number of students, that is
Total cos = 4n
Since, they are to pay $140 , for publicity, then the total cost becomes
T = 4n - 140
From the last statement
4n - 140 ≥ 640
4n ≥ 640 + 140
4n ≥780
n ≥ 780/4
n ≥ 195
That means at least 195 students must attend if the science club is to earn at least $ 640
Answer: 43.4
Step-by-step explanation: if it was dilated by a bigger number than 1 then it’s goin to have a bigger area and in this case it was dilated by
4 2/3 so you multiply the area by 4 2/3 to round your answer to the nearest tenth and u get 43.4
Answer:
Step-by-step explanation:
You need to complete the square.
C(x) = 0.02(x^2 - 1000x ...) + 11000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 11000 - 5000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 6000
C(x) = 0.02(x - 500)^2 + 6000
Now if you look at the answer you will find that the square is completed. That means that number of tractors you could produce is 500 at a cost of 6000
There is a flow to this question that you may have trouble understanding.
First of all the 500^2. That comes from taking 1/2 of 1000 and squaring it. That's what you need to complete the square.
Bur that is not what you have adding into the equation. Remember that there is a 0.02 in front of the brackets.
500^2 = 250000
0.02 * 250000 = 5000
So that number must be subtracted to make the square = 0. When you remove the brackets, you should get 11000 all in all.
So what you have outside the brackets is 11000 - 5000 = 6000
The rest is just standard for completing the square.