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xxMikexx [17]
4 years ago
7

The force on a current-carrying wire is maximum when the current is moving at what angle to the magnetic field

Physics
2 answers:
Lesechka [4]4 years ago
6 0
Perpendicular. If a current carrying wire is placed in a magnetic field perpendicular to the wire it experiences a maximum force
mezya [45]4 years ago
6 0

<u>Answer:</u> The force will be maximum when the current is moving at an angle of 90°

<u>Explanation:</u>

The relationship between the force on a current carrying wire and magnetic field is given by the formula:

\overrightarrow{F}=\overrightarrow{I}L\times \overrightarrow{B}\\\\\overrightarrow{F}=ILB\sin \theta

where,

I = current flowing through wire

B = magnetic field

L = length of the wire

F = force on a current-carrying wire

The value of \sin \theta is maximum for 90°, which is 1.

Hence, the force will be maximum when the current is moving at an angle of 90°

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If 7 ounces of a sports drink contains 110 milligrams of sodium, what is the total number of milligrams of sodium in 20 ounces o
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3 years ago
ASAP
scoundrel [369]

Answer:

A

Explanation:

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5 0
3 years ago
A 72.9-kg base runner begins his slide into second base when moving at a speed of 4.02 m/s. The coefficient of friction between
elena-14-01-66 [18.8K]

Answer:

-589.05 J

Explanation:

Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner

So, W = ΔK

W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)

So, substituting the values of the variables into the equation, we have

W = 1/2m(v₁² - v₀²)

W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)

W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)

W = 1/2 × 72.9 kg(-16.1604 m²/s²)

W = 1/2 × (-1178.09316 kgm²/s²)

W = -589.04658 kgm²/s²

W = -589.047 J

W ≅ -589.05 J

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3 years ago
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4 years ago
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