The velocity of a particle moving along the x axis is given for 1> 0 by v: = (32.0t - 2.00t^3) m/s,
2 answers:
Answer v = 32.0 t − 2.00 t³
Acceleration is the derivative of velocity.
a = dv/dt
a = 32.0 − 6.00 t²
At maximum displacement, v = 0 and a < 0.
v = 0
32.0 t − 2.00 t³ = 0
2.00 t (16.0 − t²) = 0
t = 0 or 4.00
When t = 0 s, a = 32.0 m/s².
When t = 4.00 s, a = -64.0 m/s².
Explanation:
Answer:
-64.0 m/s²
Explanation:
v = 32.0 t − 2.00 t³
Acceleration is the derivative of velocity.
a = dv/dt
a = 32.0 − 6.00 t²
At maximum displacement, v = 0 and a < 0.
v = 0
32.0 t − 2.00 t³ = 0
2.00 t (16.0 − t²) = 0
t = 0 or 4.00
When t = 0 s, a = 32.0 m/s².
When t = 4.00 s, a = -64.0 m/s².
The maximum displacement is at t = 4.00 s. Therefore, the acceleration at that moment is -64.0 m/s².
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