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igomit [66]
3 years ago
12

The velocity of a particle moving along the x axis is given for 1> 0 by v: = (32.0t - 2.00t^3) m/s,

Physics
2 answers:
devlian [24]3 years ago
7 0

Answer v = 32.0 t − 2.00 t³

Acceleration is the derivative of velocity.

a = dv/dt

a = 32.0 − 6.00 t²

At maximum displacement, v = 0 and a < 0.

v = 0

32.0 t − 2.00 t³ = 0

2.00 t (16.0 − t²) = 0

t = 0 or 4.00

When t = 0 s, a = 32.0 m/s².

When t = 4.00 s, a = -64.0 m/s².

Explanation:

Vitek1552 [10]3 years ago
3 0

Answer:

-64.0 m/s²

Explanation:

v = 32.0 t − 2.00 t³

Acceleration is the derivative of velocity.

a = dv/dt

a = 32.0 − 6.00 t²

At maximum displacement, v = 0 and a < 0.

v = 0

32.0 t − 2.00 t³ = 0

2.00 t (16.0 − t²) = 0

t = 0 or 4.00

When t = 0 s, a = 32.0 m/s².

When t = 4.00 s, a = -64.0 m/s².

The maximum displacement is at t = 4.00 s.  Therefore, the acceleration at that moment is -64.0 m/s².

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