<span>Mass of the block m = 3.3kg
Angle of the slide = 30 degrees
Distance the block slides s = 2.10 m
Time taken to slide t = 1.6 s
Initially in rest condition so initial velocity u = 0.
We have an equation for distance s = (u x t) + (1/2) x (a t^2)
s = (0 x t) + (1/2) x (a x (1.6) ^2) => 2.10 = (1/2) x (a x2.56)
2.56a = 4.20 => a = 1.64
So the magnitude of the Acceleration a = 1.64 m/s^2</span>
Answer:
Ep = 0.6095 [J]
Explanation:
As defined in the problem statement, potential energy is defined as the product of mass by gravity by height. But first we must convert all the values given to measures of the international system (SI)
g = gravity = 10 [m/s^2]
h = elevation = 40 [ft] = 12.19 [m]
m = mass = 5 [g] = 0.005 [kg]
Ep = potential energy [J]
Ep = 0.005*10*12.19 = 0.6095 [J]
Acceleration. If the line is linear on a velocity time graph, the acceleration does not change, meaning its 0
Answer:
a= 8.74 m/s²
Explanation:
Given that
m = 21 kg
θ = 13◦
F= 210 N
g= 9.8 m/s²
The force due to gravity
F₁= m g sinθ
F₁=12 x 9.8 x sin 13◦
F₁=26.45 N
Lets take acceleration is a m/s²
Form Newtons second law
F - F₁ = m a
210 - 26.45 = 21 x a
a= 8.74 m/s²
Answer:
V= 2.7 [v]
Explanation:
The value of the resistance is given by:
so:
We can calulate the voltage dropped using the Ohm's law:
