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Inessa [10]
2 years ago
8

1

Physics
1 answer:
Ray Of Light [21]2 years ago
4 0

Acceleration = Force \ mass

0,375N/0,60kg=0.6ms-2

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A two-track mind means that:
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D. your brain is processing things on the conscious and unconscious

levels​.

Explanation:

Consciousness is the awareness of ourselves and our environment.The two-track mind means that perception, memory, thinking, language, and attitude all operate on two levels conscious and unconscious level.

Glad to help!!

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An object pulled to the right by two forces has an acceleration of 2.5m/s2. The free-body diagram shows the forces acting on the
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490 N is the correct answer.

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3 years ago
One molecule of bromine (Br2) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the pro
Liula [17]

In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.

Let's consider the balanced equation for the reaction between 1 molecule of bromine and 2 molecules of potassium chloride. This is a single replacement reaction.

Br₂ + 2 KCl ⇒ 2 KBr + Cl₂

We obtain as products, 2 molecules of potassium bromide and 1 molecule of chlorine.

  • 1 molecule of KBr has 2 atoms, so 2 molecules contribute with 4 atoms.
  • 1 molecule of Cl₂ has 2 atoms.
  • The 4 atoms from KBr and the 2 atoms from Cl₂ make a total of 6 atoms.

In the reaction between 1 molecule of bromine and 2 molecules of potassium chloride, there are six atoms in the products.

Learn more: brainly.com/question/21850455

5 0
3 years ago
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A teapot with a surface area of 700 cm2 is to be plated with silver. It is attached to the negative electrode of an electrolytic
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4 years ago
An object with velocity 141 ft/s has a kinetic energy of 1558.71 ft∙lbf, on a planet whose gravity is 31.5 ft/s2. What is its
Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m  = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \  \times \ \ \ \ 1   \ lbf\ }

m  = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm

Therefore, the mass of the object is 5.045 lbm.

6 0
3 years ago
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