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3 years ago

What is force applied per unit area

Physics

2 answers:

Marizza181 [45]3 years ago

3 0

Answer:

Pressure is defined as force per unit area. The standard unit for pressure is the Pascal, which is a Newton per square meter.

P= A/F

KiRa [710]3 years ago

3 0

Answer:

force per unit area - the force applied to a unit area of surface; measured in pascals (SI unit) or in dynes (cgs unit); "the compressed gas exerts an increased pressure" pressure, pressure level.

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How many atoms are in a molecule of C6H12O6?

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hoa [83]

Answer:

The correct wording is

Pressure increases with the depth of the fluid.
A plane's engines produce thrust to push the plane forward.
A fluid can be a liquid or a gas.
A hydraulic device uses Pascal's principle to lift or move objects.
lift is the upward force exerted on objects by fluids.

Explanation:

1. As you go deeper into a fluid, there is more of it on top of you; therefore, the pressure excreted on you is greater.

2. A plane's engines pushes the air in opposite direction, which according to newton's third law, produces necessary force to move the plane forward.

3. A fluid has no fixed shape, and it deforms under the influence of external forces applied—liquid and gases fit into this definition.

4. Pascal's principle says that pressure applied on one region of the fluid must equal pressure transmitted to another region of the same fluid. This principle is used in a hydraulic device to exert forces on fluids to lift objects that would otherwise be difficult to move.

5. By definition, the upward force exerted by the fluids on objects is the lift.

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3 years ago

Use the work—energy theorem to solve each of these problems. You can use Newton's laws to check your answers. Neglect air resist

andreyandreev [35.5K]

Answer:

a) It is moving at $43.15\frac{m}{s^{2}}$ when reaches the ground.

b) It is moving at $101.44\frac{m}{s^{2}}$ when reaches the ground.

Explanation:

Work energy theorem states that the total work on a body is equal its change in kinetic energy, this is:

$W=K_f-K_i$ (1)

with W the total work, Ki the initial kinetic energy and Kf the final kinetic energy. Kinetic energy is defined as:

$K=\frac{mv^2}{2}$ (2)

with m the mass and v the velocity.

Using (2) on (1):

$W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}$ (3)

In both cases the total work while the objects are in the air is the work gravity field does on them. Work is force times the displacement, so in our case is weight (w=mg) of the object times displacement (d):

$W=Fd=wd=mgd$ (4)

Using (4) on (3):

$mgd=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}$ (5)

That's the equation we're going to use on a) and b).

a) Because the branch started form rest initial velocity (vi) is equal zero, using this and solving (5) for final velocity:

$v_f=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*95}$

$v_f=43.15\frac{m}{s^{2}}$

b) In this case the final velocity of the boulder is instantly zero when it reaches its maximum height, another important thing to note is that in this case work is negative because weight is opposing boulder movement, so we should use -mgd:

$-mgd=-\frac{mv_i^2}{2}$