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zalisa [80]
3 years ago
5

Please help! (Numbers 1 and 2)

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0
1. is 8
2. is 4

Subtract them by the percentage
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First combine the like terms in 4F + (-21)+10 F
vovikov84 [41]

Answer:

7(2f-3)

No step-by-step explanation.Sorry!

6 0
2 years ago
The fish population in a certain lake rises and falls according to the formula F = 3000(23 + 11t − t2). Here F is the number of
Gemiola [76]

Answer:

a) On January 1, 2017 the fish population will be the same as the initial population.

b) On September 18th, 2018 the fish population will be zero.

Step-by-step explanation:

Hi there!

a) First, let´s write the function:

F(t) = 3000(23 + 11t − t²)

The population on January 1, 2006 is the population at t = 0. Then:

F(0) = 3000(23 + 11· 0 - 0²)

F(0) = 3000 · 23 = 69000

This will be the population every time at which t² - 11t = 0. Then let´s find the other value of t (besides t = 0) that makes that expression to be zero:

t² - 11t = 0

t(t - 11) = 0

t = 0

and

t - 11 = 0

t = 11

On January 1, 2017 (2006 + 11), the fish population will be the same as the initial population.

b) We have to obtain the value of t at which F(t) = 0

F(t) = 3000(23 + 11t − t²)

0 = 3000(23 + 11t − t²)

divide both sides of the equation by 3000

0 = 23 + 11t − t²

Let´s solve this quadratic equation using the quadratic formula:

a = -1

b = 11

c = 23

x = [-b ± √(b² - 4ac)] / 2a

x = 12.8  ( the other value of x is negative and therefore discarded).

After 12.8 years all the fish in the lake will have died.

If 1 year is 12 months, 0.8 years will be:

0.8 years · 12 months/year = 9.6 months

If 1 month is 30 days, 0.6 month will be:

0.6 month · 30 days / month = 18 days

All the fish will have died after 12 years, 9 months and 18 days from January 1, 2006. That is, on September 18th, 2018.

7 0
3 years ago
HELP TUTOR…<br> ss<br> z<br> z<br> z<br> z
kondor19780726 [428]

Answer:

A)σ = 15.37 miles per hour

B) σ = 55.10 miles per hour

C) 39.73 miles per hour

Step-by-step explanation:

Formula for standard deviation is;

σ = √(Σ(x - μ)²)/(n - 1)

A) For large wild cats;

μ = Σx/n = (70 + 40 + 30 + 40 + 35 + 35 + 35 + 35 + 10)/9 = 36.67

σ = √((70 - 36.67)² + (40 - 36.67)² + (30 - 36.67)² + (40 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (10 - 36.67)²)/(9 - 1)

σ = √236.1139

σ = 15.37

B) For various birds;

μ = Σx/n = (218 + 106 + 97 + 56 + 66 + 39 + 55 + 32 + 54 + 20 + 25 + 25)/12

μ = 66.0833

σ = √((218 - 66.0833)² + (106 - 66.0833)² + (97 - 66.0833)² + (56 - 66.0833)² + (66 - 66.0833)² + (39 - 66.0833)² + (55 - 66.0833)² + (32 - 66.0833)² + (54 - 66.0833)² + (20 - 66.0833)² + (25 - 66.0833)² + (25 - 66.0833)²)/(12 - 1)

σ = √3035.72

σ = 55.10

C) difference in standard deviations = 55.10 - 15.37 = 39.73 miles per hour

8 0
3 years ago
Two binders costs$4.36. how many bindees can buy with $55?​
Reil [10]

Answer:

Step-by-step explanation:

First you need to find the price for one binder. If 2 binders cost 4.36 you have to divide by 2 to find the price for 1. You should get 2.18. Then you have to see how many times you can multiply 2.18 without having the product go over 2.18. 2.18 • 22 = 47.96, the number closest to 50 without going over. Therefore, she can buy 22 binders.

6 0
3 years ago
Read 2 more answers
Below is a probability distribution for the number of failures in an elementary statistics course. X 0 1 2 3 4 P(X=x) 0.41 0.18
faust18 [17]

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29

b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59

c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88

d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12

e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24

f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59

3 0
3 years ago
Read 2 more answers
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