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1 year ago

Hurry need the answer asap

Chemistry

1 answer:

Soloha48 [4]1 year ago

7 0

P,T,Y refers to the set of points which are collinear and is therefore denoted as option C.

<h3>What are Collinear points?</h3>

This is commonly used in geometry and refers to the set of points which lie on the same straight line and are always close to each other when compared to other points. It is possible for them to appear on different planes only and the value by the triangle from the three points is usually zero.

In the example give, only P,T and Y are the points which lie on the same line while other options have points which lie on different lines thereby making them incorrect.

This is therefore the reason why option C was chosen as the most appropriate choice.

Read more about Collinear points here brainly.com/question/18559402

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A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

3 years ago

A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law

zysi [14]

621.4L

Explanation:

Given parameters:

Initial volume = 547L

Initial temperature = 331K

Final temperature = 376K

Unknown:

Final volume = ?

Solution:

The appropriate gas law to use is the Charles's law.

The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.

The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

V₁ is the initial volume

T₁ is the initial temperature

V₂ is the final volume

T₂ is the final temperature

Since the unknown is the final volume, we make it the subject of the expression;

V₂ = $\frac{V_{1} }{T_{1} } x T_{2} = \frac{547}{331 } x 376$

V₂ = 621.4L

learn more:

Boyle's law brainly.com/question/8928288

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miskamm [114]

The answer is molar mass to MO2SO4

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Please help I will mark brainy

Artyom0805 [142]

Answer:

the answer is c I took the test

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It is 30292
$2 \times 2 \sqrt[ > ]{?}$

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