Answer:
Percent yield = 50%
Explanation:
Given data:
Mass of CH₄ = 16 g
Mass of O₂ = 32 g
Mass of CO₂ = 11 g
Percent yield of CO₂ = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass/ molar mass
Number of moles = 16 g /16 g/mol
Number of moles = 1 mol
Number of moles of O₂:
Number of moles = mass/ molar mass
Number of moles = 32 g /32 g/mol
Number of moles = 1 mol
Now we will compare the moles of CO₂ with both reactant.
O₂ : CO₂
2 : 1
1 : 1/2×1= 0.5 mol
CH₄ : CO₂
1 : 1
Number of moles of CO₂ produced by oxygen are less so it will limiting reactant.
Theoretical yield:
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.5 mol × 44 g/mol
Mass = 22 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 11 g/ 22 g × 100
Percent yield = 50%
Base is used in aldol condensation reaction
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Answer:
b.) methane and long branches alkanes
Explanation:
Petroleum or crude oil is a fossil fuel formed by the decomposition of organisms buried under the earth's surface and subjected to intense pressure and temperature. It is composed of a mixture of hydrocarbons which include paraffins (linear and branched alkanes), naphthenes (cyclic alkanes) and other aromatic compounds.
However, petroleum is predominantly consists of paraffins which have the general formula CnH2n+2 and include methane and other long branched alkanes.
Answer:
No.
Explanation: You cannot change the formulas of individual substances because the chemical formula for a given substance is characteristic of that substance.