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sveticcg [70]
3 years ago
12

Gold is reacted with Bromine gas according to the reaction 2Au + 3Br2 → 2AuBr3 . Use the data table below to determine the perce

nt yield of Gold Bromide.
Mass of Gold Mass of Bromine Theoretical Yield Actual Yield

39.4g 15.0g ? 12.3


A: 97.29%

B: 45.02%

C: 89.5%

D: 86.42%

NEED HELP FAST!
Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0
These link people are annoying
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At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
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Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

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x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

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equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

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= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

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