77.
To find the answer u have to subtract the atomic mass from the atomic number.
Answer:
= 8350 joules
Solution and explanation:
- The heat of fusion refers to the quantity of heat released when a given amount of water freezes.
- For example, 1 g of water releases 334 J when it freezes at 0°C.
Therefore; For 25.0 g of water.
Heat released = Mass of water × heat of fusion
= 25 g × 334 J/g
= 8350 Joules
Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.
Answer: Thus 663 J of heat is released when 27.6 g 
cools from 83.1 °C to 55.6 °C
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat released = ?
m = mass of substance = 27.6 g
C = specific heat capacity = 
Initial temperature= 
= 
Final temperature = 
= 
Change in temperature ,
Putting in the values, we get:
As the value of q is negative, it means the heat has been released and it is 663J
1. The box like figure in the given image is the [BATTERY SOURCE] from where the current drawn into the circuit.
2. A string connecting positive terminal of battery to the bulb is an [ELECTRIC WIRE] through which current flows in the circuit.
3. A bubble like object in the circuit is a [BULB] which lights up when current moves through the circuit.
4. A component connected to the negative terminal of batter source is a [SWITCH].
The answer are uppercase.
I hope this helps c:
