X_>-42
sorry, i cant do the arrow thing on my keyboard, but it’s the same arrow in the picture
find the prime factors of each term in order to find the GCF
answer is pq^2
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>
According to the question,
- Diameter of circle = 16 in
We are asked to calculate it’s circumference in terms of π.
★ Circumference of circle = 2πr
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Let us first calculate the radius of the circle.
→ Diameter = 2 × Radius
→ 16 in = 2r
→ r = 16 in ÷ 2
→ r = 8 in
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Substituting values in the formula of circumference,
→ C = 2πr
→ C = (2 × π × 8) in
→ C = 16π in
<u>Therefore</u><u>,</u><u> </u><u>1</u><u>6</u><u>π</u><u> </u><u>inches</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer:
-(23/6)π
-(19/6)π
-3π
Step-by-step explanation:
cos2t=cos^2t-sin^2t => cos^2t=1-sin^2t =>cos2t=1-2sin^2t
sint=1-2sin^2t, if x=sint, thenn we have 2x^2+x-1=0
Here x=0.5, x=-1, as x=sint => sint = -1 solutions for -4π to -2π is t=-3π,
sint = 0.5 solutions for -4π to -2π is t= -(23/6)*π, and t = -(19/6)*π
