C3H8 + 5O2 ------> 3CO2 + 4H2O
from reaction 1 mol 5 mol
given 1.82 mol x mol
x=(1.82*5)/1 = 9.10 mol CO2
Answer:
V = 1.434 L
Explanation:
Given data:
Mass of argon = 4.24 g
Temperature = 58.2 °C
Pressure = 1528 torr
Volume = ?
Solution:
58.2 °C = 58.2 + 273 = 331.2 K
1528/760= 2.01 atm
<em>Number of moles:</em>
Number of moles = mass/molar mass
Number of moles = 4.24 g / 39.948 g/mol
Number of moles = 0.106 mol
<em>Volume:</em>
PV = nRT
V = nRT/P
V = 0.106 mol ×0.0821. atm. L. mol⁻¹. K⁻¹ × 331.2K/ 2.01 atm
V = 2.88 atm L/ 2.01 atm
V = 1.434 L
Explanation:
As density is defined as the mass of a substance divided by its volume.
Mathematically, Density = 
It is given that mass is 50 g and density is 0.934
.
Hence, calculate the volume of methyl acetate as follows.
Density = 
0.934
= 
Volume = 
or, =
(as 1
= 1 mL)
Thus, we can conclude that the volume of methyl acetate the student should pour out is
.
If Liquid 1 has a higher specific heat than Liquid 2, then Liquid 1 will take longer to increase in temperature because the higher specific heat of a liquid needs more thermal energy for heating a liquid.
<h3>What is specific heat?</h3>
Specific heat of a substance refers to the quantity of heat that is required to raise the temperature of one gram of a substance by one Celsius degree so we can conclude that Liquid 1 will take longer to increase in temperature
Learn more about heat here: brainly.com/question/24390373
Cyclohexanol is an Alcohol..........