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slamgirl [31]
3 years ago
12

I NEED HELP ASAP :)

Chemistry
1 answer:
White raven [17]3 years ago
4 0

C) \text{LiBr}_{3}

Explanations

Approach A: Comparison of the bonding atoms

What element(s) does each species comprise?

  • carbon monoxide- one metalloid, carbon, bonded to one nonmetal
  • oxygen- one nonmetal
  • lithium bromide- one metal and one nonmetal
  • ammonia- two nonmetals

Lithium bromide \text{LiBr}_{3} is the only substance that features a metal element bonded to a nonmetal element among all four species in the list. It takes significant differences in electronegativity for the bonding atoms in a binary compound to ionize and form an ionic compound. Therefore the species in question shall  contain at least one metal element bonded to one nonmetal.

Approach B: Comparison of melting points

Recall the physical state of the species under room temperature and pressure:

  • carbon monoxide- gas
  • oxygen- gas
  • lithium bromide- ?
  • ammonia- gas

Ionic bonds hold ions in an ionic compound in place with great degrees of rigidity. In contrast, covalent molecules adhere to each other with intermolecular interactions that are weaker by magnitudes. It's unlikely for ionic crystals to behave as gases under standard conditions. Thus A, B, D cannot be ionic compounds.

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Answer: The moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the moon and the side farthest from the moon. These bulges of water are high tides

Explanation:

3 0
3 years ago
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What is the molarity of 2.50 mol in a 1000 ml solution? *
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Explanation:

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What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?
ArbitrLikvidat [17]
Data:

m (<span>Sample Mass) = ? 
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (Hg_{2}  Cl_{2})
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass Hg_{2} Cl_{2} = 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

n =  \frac{m}{MM}

Solving:


n = \frac{m}{MM}
0.714 =  \frac{m}{472.09}
m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark

Answer:
By approximation would be letter D) <span>337.2 g</span>


8 0
3 years ago
Describe the properties of alkali metals. based on their electronic arrangement, explain whether they exist alone in nature.
saul85 [17]

The alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.

<h3>What are the  properties of alkali metals?</h3>

The alkali metals have the high thermal and electrical conductivity. It has high lustre, ductility, and malleability as compared to other materials. Each alkali metal atom has one electron in its outermost shell which make more reactive.

So we can conclude that the alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.

Learn more about metal here: brainly.com/question/25597694

#SPJ1

5 0
2 years ago
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kati45 [8]

Answ????

Explanation:

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