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slamgirl [31]
3 years ago
12

I NEED HELP ASAP :)

Chemistry
1 answer:
White raven [17]3 years ago
4 0

C) \text{LiBr}_{3}

Explanations

Approach A: Comparison of the bonding atoms

What element(s) does each species comprise?

  • carbon monoxide- one metalloid, carbon, bonded to one nonmetal
  • oxygen- one nonmetal
  • lithium bromide- one metal and one nonmetal
  • ammonia- two nonmetals

Lithium bromide \text{LiBr}_{3} is the only substance that features a metal element bonded to a nonmetal element among all four species in the list. It takes significant differences in electronegativity for the bonding atoms in a binary compound to ionize and form an ionic compound. Therefore the species in question shall  contain at least one metal element bonded to one nonmetal.

Approach B: Comparison of melting points

Recall the physical state of the species under room temperature and pressure:

  • carbon monoxide- gas
  • oxygen- gas
  • lithium bromide- ?
  • ammonia- gas

Ionic bonds hold ions in an ionic compound in place with great degrees of rigidity. In contrast, covalent molecules adhere to each other with intermolecular interactions that are weaker by magnitudes. It's unlikely for ionic crystals to behave as gases under standard conditions. Thus A, B, D cannot be ionic compounds.

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What dissolved species are present in a solution of NaClO4?
Nadusha1986 [10]

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3 0
3 years ago
Express the following in liters at STP:<br><br><br><br> 6.62 x 10-3 moles HF
serious [3.7K]

Answer:

The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L

Explanation:

Given data:

Number of moles of HF =  6.62×10⁻³ mol

Volume of HF in litter at STP = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Standard temperature = 273 K

Standard pressure = 1 atm

Now we will put the values in formula.

1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K

V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K   × 273 K  / 1 atm

V = 148.38×10⁻³ L

Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.

8 0
3 years ago
Heat the oxygen to about 150 K. What state of matter is this?
adelina 88 [10]

Answer:

  • <u>Gas</u>

Explanation:

It is easier if you convert the kelvin temperature into Celsius degrees:

  • ºC = T - 273.15 = 150 - 273.15 = -123.15ºC

Now, you know that that is a very cold temperature. Thus, may be the oxygen is not gas any more but it changed to liquid . . . or solid?

You must search for the boiling point and melting (freezing) point of oxygen in tables or the internet. At standard pressure (about 1 atm) they are:

  • Melting point: −218.79 °C,
  • Boiling point: −182.962 °C

That means that:

  • below -218.79ºC oxygen is solid (not our case).
  • between -218.79ºC and -182.962ºC oxygen is liquid (not our case)
  • over -182.962ºC oxygen is a gas. This is our case, because -123.15ºC is a higher temperature than -182.962ºC.

Hence, <em>the state of matter of oxygen at 150K</em>, and standard pressure, is gas.

3 0
3 years ago
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