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2 years ago

Help I really need help and don't search it on go.ogle this is a school assignment and i can get in trouble thank you sm :)

Chemistry

1 answer:

kupik [55]2 years ago

4 0

Answer:

Nuclear fission is almost 5 times times more efficient than traditional fossil fuels at producing energy. That's a lot of energy packed into a small space. Nuclear energy is more efficient, which means it uses less fuel to power the plant and produces less waste.

Explanation:

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If a measurement is said to be precise this means that it is what

Gala2k [10]

On point? Do you have any options?

6 0

3 years ago

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How much of a 24-gram sample of Radium-226 will remain unchanged at the end of three half-life periods?

shutvik [7]

Answer:

The right answer is "3 g".

Explanation:

Given:

Initial mass substance,

$M_0=24 \ g$

By using the relation between half lives and amount of substances will be:

⇒ $M=\frac{M_0}{2^n}$

$=\frac{24}{2^3}$

$=3 \ g$

Thus, the above is the correct answer.

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3 years ago

What is the precipitate for CuSO4+NaOH<br> (Balancing Equations)

jeka57 [31]

Answer:

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

Explanation:

5 0

3 years ago

A student heats 10.52 g of sodium hydrogen carbonate in a crucible until the compound completely decomposes to sodium carbonate

saveliy_v [14]

Answer:

$m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3$

Explanation:

Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

$2NaHCO_3(s)\rightarrow Na_2CO_3(s)+H_2O(g)+CO_2(g)$

Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

$m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3} *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3$

Best regards!

4 0

2 years ago

PLS help

viktelen [127]

Answer:

d . Sc2O5

Explanation:

Hello,

In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

$Sc^{+5}_2O^{-2}_5$

For that reason, the answer is d . Sc2O5

Best regards.

3 0

3 years ago

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