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Dmitriy789 [7]
3 years ago
11

Identify the scientist associated with each major contribution to the development of atomic theory. He discovered the electron.

He discovered periodic changes in properties of elements when they are listed in order of their atomic weights. He experimented with the deflection of cathode rays by a magnetic field. He carried out experiments, using gold foil, that measured the scattering of positively charged alpha particles by heavy atoms. He proposed that atoms are the basic units of matter. He proposed the model of the atom had most of its mass concentrated in a very small nucleus. He proposed that in a chemical reaction, atoms are neither created nor destroyed. Answer Bank
Chemistry
1 answer:
Debora [2.8K]3 years ago
8 0

Answer:

He discovered the electron- J.J Thompson

He discovered periodic changes in properties of elements when they are listed in order of their atomic weights- Dimitri Mendeleev

He experimented with the deflection of cathode rays by a magnetic field- J.J Thompson

He carried out experiments, using gold foil, that measured the scattering of positively charged alpha particles by heavy atoms- Ernest Rutherford

He proposed that atoms are the basic units of matter- John Dalton

He proposed the model of the atom had most of its mass concentrated in a very small nucleus- Ernest Rutherford

He proposed that in a chemical reaction, atoms are neither created nor destroyed-John Dalton

Explanation:

J.J Thompson was the discoverer of the electrons. He also worked hard to show that they were negatively charged particles after he experimented with them using a magnetic field. He named them cathode rays.

Dimitri Mendeleev  found that, when all the known chemical elements were arranged in order of increasing atomic weight, the resulting table displayed a recurring pattern, or periodicity, of properties within groups of elements(Encyclopedia Britannica).

Ernest Rutherford demonstrated by experiment using a thin gold foil and alpha particles that the atoms are composed of a positive massive core called the nucleus.

John Dalton proposed that matter is composed of atoms. Also, in a chemical reaction, atoms are neither created nor destroyed.

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Why is specific activity used as a measurement of enzyme purity, but the turnover number cannot be used for this purpose?
Lelechka [254]

Answer:

See explanation

Explanation:

Specific activity of an enzyme is defined as a measure of the rate of reaction between enzyme and substrate.

In the study of enzyme kinetics, specific activity is particularly regarded to be the amount of substrate converted by the enzyme per milligram of protein per unit of time. It is thus a reliable measure of enzyme activity per milligram of total protein.

On the other hand, the turnover number is defined as a measure of the number of conversions achieved by a substrate molecule in one second at a particular active site depending on the specific enzyme concentration.

Since specific activityof the enzyme is the ratio of the enzyme activity to enzyme concentration, then specific activity can be used as a measurement of enzyme purity.

4 0
3 years ago
The heat of vaporization for benzaldehyde is 48.8 kj/mol, and its normal boiling point is 451.0 k. use this information to deter
user100 [1]

Answer:

The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

Explanation:

  • To solve this problem, we use Clausius Clapeyron equation: ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂).
  • The first case: P₁ = 1 atm = 760 torr and T₁ = 451.0 K.
  • The second case: P₂ = <em>??? needed to be calculated</em> and T₂ = 61.5 °C = 334.5 K.
  • ΔHvap = 48.8 KJ/mole = 48.8 x 10³ J/mole and R = 8.314 J/mole.K.
  • Now, ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂)
  • ln(760 torr /P₂) = (48.8 x 10³ J/mole / 8.314 J/mole.K) (1/451 K - 1/334.5 K)
  • ln(760 torr /P₂) = (5869.62) (-7.722 x 10⁻⁴) = -4.53.
  • (760 torr /P₂) = 0.01075
  • Then, P₂ = (760 torr) / (0.01075) = 70691.73 torr.

So, The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

7 0
3 years ago
How do you solve this?4. How many km are equal to 1.55 x 10^4 m?
katrin [286]

Answer:

15.5 km

Explanation:

1.55 x 10^4 m means 1.55 x 10000 = 15,500 m

1 km = 1000 meters

To convert to km we divide by 1000

So 15,500/1000

= 15.5 km

4 0
3 years ago
18. How many moles of atoms are there in each of
Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

                     

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

                   = 1 mole

The number of moles calculated by Avogadro's number in 3.01*10^23 of  Mg

3.2*10^23=1/6.23*10^23

                = 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

  = 3.25*10^5/ 207

  = 1570 moles of Pb.

Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

                            =  2.18125*10^-13 moles of oxygen.

3 0
3 years ago
A scientist is measuring the rate of an enzyme-catalyzed reaction that produces a red-colored product. as the solution containin
slavikrds [6]
The answer would be A will increase and T <span>will decrease.

The product of this reaction emits red light because it absorbs green and blue light. As the reaction occurs, the concentration of the product increase. This will makes absorbance of green and blue light increases and the solution will become redder.</span>
8 0
3 years ago
Read 2 more answers
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