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riadik2000 [5.3K]
1 year ago
7

Arrange the following in order from least to greatest 3 4. π/2, 0.5, √4

Mathematics
1 answer:
Olenka [21]1 year ago
4 0

Answer:

0.5, pi/2, square root of 4, and im assuming you meant to put 3.4 for the first number so that is the greatest number.

Step-by-step explanation:

set 0.5 and 3.4 aside since they are normal numbers. the square root of 4 is 2 since 2 squared = 4. to figure out pi/2, divide 3.14 by 2 (3.14 is pi) which is 1.57.

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the price of an article is Marked 25% above the cost price .if it is solid the profit of Rs.500 after allowing 15% discount .wha
gavmur [86]

Answer:

  Rs 8500

Step-by-step explanation:

For a cost price of c, the marked price is ...

  marked = c +25%·c = 1.25c

After the 15% discount, the sale price will be ...

  s = marked -15%·marked = 0.85·marked = (0.85)(1.25c) = 1.0625c

The profit will be the difference between the sale price s and the cost c:

  p = s -c

  500 = (1.0625c) -c = 0.0625c

Then the cost is ...

  500/0.0625 = c = 8000

and the sale price is ...

  s = c +p = 8000 +500 = 8500 . . . rupees

The selling price will be Rs 8500.

8 0
2 years ago
Select all the statements about rotations that are true.
sladkih [1.3K]

Answer: we dont have options

Step-by-step explanation:

7 0
3 years ago
Can someone help me with this question please
Ne4ueva [31]
Start with the given equation.

P1V1=P2V2

To solve for P2, move anything else on that side to the other side so that P2 is alone.

P1V1=P2V2
P2=P1V1/V2
8 0
3 years ago
Steps to answer -3(x+4)+15=6-4x
Mariana [72]
  1. distribute| -3x-12+15 = 6-4x
  2. simplify| -3x+3=6-4x
  3. solve by getting X to one side| -3=1x
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8 0
3 years ago
A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.
Tanzania [10]

Answer: The height of the container is 10 centimeters. If its diameter and height were both doubled, the container's capacity would be 8 times its original capacity.

Step-by-step explanation:

The volume of a cone can be calculated with this formula:

V=\frac{\pi r^2h}{3}

Where "r" is the radius and "h" is the height.

We know that the radius is half the diameter. Then:

r=\frac{12cm}{2}=6cm

We know the volume and the radius of the conical container, then we can find "h":

120\pi cm^3=\frac{\pi (6cm)^2h}{3}\\\\(3)(120\pi cm^3)=\pi (6cm)^2h\\\\h=\frac{3(120\pi cm^3)}{\pi (6cm)^2}\\\\h=10cm

The diameter and height doubled are:

d=12cm*2=24cm\\h=10cm*2=20cm

Now the radius is:

r=\frac{24cm}{2}=12cm

And the container capacity is

V=\frac{\pi (12cm)^2(20cm)}{3}=960\pi cm^3

Then, to compare the capacities, we can divide this new capacity by the original:

 \frac{960\pi cm^3}{120\pi cm^3}=8

Therefore,  the container's capacity would be 8 times its original capacity.

6 0
3 years ago
Read 2 more answers
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