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garri49 [273]
2 years ago
15

How many different ordered pairs (x, y) are there suchthat x is an even integer, where 4 <= x <= 10, and y isan integer, w

here 4 < y < 10 ?(A) 8(B) 12(C) 20(D) 30(E) 36
Mathematics
1 answer:
german2 years ago
7 0

Correct option is C. There are 20 ordered pairs.

Given that ordered pairs (x,y)

such that x is even integer where 4≤x≤10 and y is an integer.

where 4<y<10.

Then even integer 4≤x≤10 are four i:e

4,6,8,10

And integer 4<y<10 are five i:e

5,6,7,8,9

Then ordered pair are = 4×5=20

<h3>What are ordered pairs?</h3>

An ordered pair is a composition of the x coordinate (abscissa) and the y coordinate (ordinate), having two values written in a fixed order within parentheses. It helps to locate a point on the Cartesian plane for better visual comprehension. The numeric values in an ordered pair can be integers or fractions.

To learn more about ordered pairs from given link

brainly.com/question/1528681

#SPJ4

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Use the quadratic expression 25x2−y2 to answer the questions.
vova2212 [387]

Answer:

Part A)

This quadratic expression can be factored by using the difference of squares pattern.

Part B) (5x+y) and (5x-y)

Step-by-step explanation:

Given:

25x^2-y^2

above polynomial can be factorize by using difference of squares formula

a2-b2=(a+b)(a-b)

25x^2-y^2= (5x-y)(5x+y)

so for part A)

correct option is  This quadratic expression can be factored by using the difference of squares pattern.

Part B)

As factored above in part A,

the factors of given polynomial 25x^2-y^2 are (5x+y)(5x-y)

so for part B) correct options are (5x+y) and (5x-y) !

8 0
4 years ago
Two pieces of lengths 13/3 m and 3/5 m are cut off from a rope 15
garri49 [273]

Hello there! ;) The way you solve this type of problem is you must find common denominators. So simplify 13/3= 4 1/3. So we can do 1/3*5/5=5/15. Next we must do 3/5*3/3= 9/15. So add 5/15+9/15= 14/15. And add the 4+ 14/15=          4 14/15. So then you must subtract 15 - 4 14/15= 10 1/15 I believe. I believe 10 1/15 is the remainder of the rope. You might want to check in with someone else though.

Hope I help! :D

5 0
4 years ago
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