Question

Mindy drew a figure by drawing squares and parts of circles as shown below. What is

Answer 1

The area of Mindy's figure in square inches is 1250$\pi$+5000.

Given the figure contain two squares of side length= 50 inches and two-quarter circles of radius=50 inches

The area of the square is $(length of side)^{2}$        

The area of a quarter of the circle is $\frac{\pi r^{2} }{4}$

The area of the square= $(50 inches)^{2}$ {as the length of the side of the square is 50 inches}

The area of the square= 2500 square inches

Therefore the area of two squares is (2500 square inches) × 2

The are two squares=5000square inches

The area of a quarter of the circle=$\frac{\pi (50 inches)^{2} }{4}$ {as the length of the radius of the circle is 50 inches}

The area of a quarter of the circle=$\frac{2500\pi }{4}$

Therefore the area of two quarters of the circle = $1250\pi$square inches

Area of Mindy's figure= area of two square's+ areas of two quarter circle

Area of Mindy's figure= 2500square inches+ $1250\pi$square inches

Area of Mindy's figure= (2500+$1250\pi$)square inches

Hence, The area of Mindy's figure in square inches is 1250$\pi$+5000.

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