Ok thanks so i i i said he will never be there till next tuesday so if you want me back at home or not and then i will give you the answer i i and i’m will give ok thanks so i i i said he will never be there till next tuesday so if you want me back at home or not and then i will give you the answer i i and i’m will give ok thanks so i i i said he will never be there till next tuesday so if you want me back at home or not and then i will give you the answer i i and i’m will give
Answer: 682
Also, each rectangle’s width is half its height. It can be expressed as
w= 1/2h<span>
The first rectangle is 32cm tall. Then the measurement would be
h=32
w= 1/2h= 16
</span>The first rectangle is 32cm tall and e<span>ach rectangle is half as tall as the previous one. That can be expressed as
h(n)= 32(1/2)^n-1
The area of rectangle is
area(n)= h*w
area(n)=h*</span> (1/2h)= 1/2h ^2
area(n)= 1/2 {32(1/2)^n-1}^2<span>
area(n)= 512(1/2)^2n-2
Then the sum of the 5 rectangle would be:
</span>area(1) + area(2) + area(3) + area(4)+ area(5)
512(1/2)^2(1)-2 + 512(1/2)^2(2)-2 + 512(1/2)^2(3)-2 + 512(1/2)^2(4)-2 +512(1/2)^2(5)-2 =
512+ 512/4 + 512/16+ 512/ 64 + 512/ 256=
512+ 128 + 32+ 8 + 2= 682
The answer is C!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I believe the answer is B
Step-by-step explanation:
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