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MissTica
3 years ago
15

There are 4 blue, 2 red, 1 brown, 1 black, 1 white, and 3 green crayons in a box. What is the probability of picking a red crayo

n, putting it back, and then picking a second
red crayon?
Mathematics
2 answers:
loris [4]3 years ago
8 0

Answer:

1/6

Step-by-step explanation:

Simply just Add the different amounts of different crayons as your denominator, and find the number of red, as your numerator. This gets you 2/12. 2/12 = 1/6

Can I be brainliest? TYSM

Travka [436]3 years ago
5 0

Answer:

1/36

Step-by-step explanation:

We have 12 Crayons total

2 of those are red

So the chance of pulling one red is 2/12

If we have to find the chance of two thing happening (Getting two reds back to back) we have to multiply our chances. Think of how its harder to get the same thing twice in a row.

So its 2/12 × 2/12 = 4/144

Simplify and get 1/ 36

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What is the VALUE of the place underlined? (Do not give the name.) 706​
Andreyy89

Answer:

There is no placed underlined in the statement of the problem.

Step-by-step explanation:

But, the 7 is in the hundreds place,

the 0 is in the tens place, and

the 6 is in the ones place.  :-))))

5 0
2 years ago
Read 2 more answers
There are 9 marbles representing 3 different colors. Write a problem where 2 marbles are selected at random without replcement a
Nata [24]
There are 9 marbles in the bag. We pick 2 without replacement and get a probability of 1/6.

Each draw of a marble has a probability associated with it. Multiplying these gives 1/6 so let us assume the probabilities are (1/3) and (1/2).

In order for the first draw to have a probability of 1/3 we need to draw a color that has (1/3)(9)=3 marbles. So let's say there are 3 red marbles. The P(a red marble is drawn) = 1/3.

Now that a marble has been drawn there are 8 marbles left. In order for the second draw to have a probability of 1/2 we must draw a color that has (1/2)(8) = 4 marbles. So let's say there are 4 blue marbles out of the 8.

Since there are 9 marbles to start and we have 3 red marbles and 4 blue marbles, the remaining 2 marbles must be a different color. Let us say they are green.

The problem is: There are 3 red marbles, 4 blue marbles and 2 green marbles in a jar. A marble is picked at random, it's color is noted and the marble is not replaced. A second marble is drawn at random and its color noted. What is the probability that the first marble is red and the second blue?
8 0
3 years ago
You scored a %95 on your math quiz this quiz was 60 points how many points did you get ?
enyata [817]

Answer:

57

Step-by-step explanation:

use a calculator lol

4 0
2 years ago
I NEED HELP PLEASE WILL MARK BRAINLIEST IF I CANNNNN
choli [55]

Answer:153.9

Step-by-step explanation:

8 0
3 years ago
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What value of x and y will make the polygon below a parallelogram?
Mrrafil [7]

Answer:

x = 4

y  =1

Step-by-step explanation:

Given

The attached figure

Required

x and y

If the attached is a parallelogram, then:

<em>Either segment of a diagonal are equal; So, we have:</em>

3x = 12

x + y = 5y

<em></em>

In 3x = 12

Divide both sides by 3

x = \frac{12}{3}

x = 4

Substitute x = 4 in x + y = 5y

4 + y = 5y

Collect like terms

5y - y =4

4y = 4

Divide both sides by 4

y = \frac{4}{4}

y  =1

5 0
3 years ago
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