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MissTica
3 years ago
15

There are 4 blue, 2 red, 1 brown, 1 black, 1 white, and 3 green crayons in a box. What is the probability of picking a red crayo

n, putting it back, and then picking a second
red crayon?
Mathematics
2 answers:
loris [4]3 years ago
8 0

Answer:

1/6

Step-by-step explanation:

Simply just Add the different amounts of different crayons as your denominator, and find the number of red, as your numerator. This gets you 2/12. 2/12 = 1/6

Can I be brainliest? TYSM

Travka [436]3 years ago
5 0

Answer:

1/36

Step-by-step explanation:

We have 12 Crayons total

2 of those are red

So the chance of pulling one red is 2/12

If we have to find the chance of two thing happening (Getting two reds back to back) we have to multiply our chances. Think of how its harder to get the same thing twice in a row.

So its 2/12 × 2/12 = 4/144

Simplify and get 1/ 36

You might be interested in
What is the 214 term in the sequence 7,10,13,16?
mixer [17]
We can figure this out using the explicit formula.

f(n)=f(1)+d(n-1)

n represents the term we are looking for.
f(1) represents the first term in the sequence, which in this case, is 7.
d represents the common difference, which in this case, is +3.

f(n) = 7 + 3(n - 1)
f(n) = 7 + 3n - 3
f(n) = 4 + 3n

Now, we can input 214 for n and solve.

f(214) = 4 + 3(214)
f(214) = 4 + 642
f(214) = 646

The 214th term in this sequence is 646.
5 0
3 years ago
mean of 164,175,178,166,167,145,176,150,174,162,180,156,173,158,182,184,160,172,186,168,195,169,171,187,170
Karo-lina-s [1.5K]

Answer:

170.72

Step-by-step explanation:

to find the mean, we must add al the numbers and divide it by n

that is,

164,175,178,166,167,145,176,150,174,162,180,156,173,158,182,184,160,172,186,168,195,169,171,187,170 we have to add al these numbers and divide it by 25

sum- 4628 divided by 25

=170.72

7 0
2 years ago
The sum of 3 integers is 194. the sum of the first and second integers exceeds the third by 80. The third integer is 45 less tha
kirill115 [55]
Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45

Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239

Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102

Solving for y,
y = -2(102) + 239
y = 35

Solving for z,
z = 102 - 45
z = 57
5 0
3 years ago
Is 1/7 greater than all of the following except<br> 1/3<br> -1<br> -2<br> -0.1
Elis [28]

Answer:

a. 1/3

Step-by-step explanation:

1/3= .33

1/7= .142

3 0
3 years ago
Read 2 more answers
Margo paid $550.00 for dance classes. She paid a $50.00 registration fee and $25.00 for each week she was enrolled in the classe
trapecia [35]

Answer:

She enrolled in the dance classes for 20 weeks

Step-by-step explanation:

* Margo paid $550.00 for dance classes

* She paid a $50.00 registration fee

* She paid $25.00 for each week she was enrolled in the classes

* We need to find the number of weeks w she enrolled in the

  dance classes

<u><em>Lets write an equation of these information and solve it</em></u>

∵ The registration fee = $50

∵ The cost of of each week = $25

∵ The number of weeks = w

She will pay $50 plus $25 times the number of the weeks

∴ She paid in the dance classes = 50 + 25 w

∵ She paid $550 for the dance classes

∴ 50 + 25 w = 550

The equation is 50 + 25 w = 550

<u><em>Lets solve the equation</em></u>

∵ 50 + 25 w = 550

Subtract 50 from both sides

∴ 25 w = 500

Divide both sides by 25

∴ w = 20

∵ w represents the number of the weeks

∵ w = 20 weeks

<em>She enrolled in the dance classes for 20 weeks</em>

5 0
3 years ago
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