Answer:
A. `1/2` foot
Step-by-step explanation:
The computation of the width of the box is shown below:
15 ÷ 28 = (5 ÷ 7)(1 1 ÷ 2)(width)
15 ÷ 28 = (5 ÷ 7)(3 ÷ 2)width
15 ÷ 28 = (15 ÷ 14)width
(15 ÷ 28) ÷ (15 ÷ 14) = width
(15 ÷ 28) × (14 ÷ 15) = width
w = 14 ÷ 28
= 1 ÷ 2 ft
Answer:
7/5
Step-by-step explanation:
3x + 5 + 2x - 12 = 0
5x - 7 = 0
5x = 7
x = 7/5
Answer:
Step-by-step explanation:
<h3>Part B</h3>
Assumed the dimensions of the top and bottom parts are identical.
Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:
- h = 1.8 cm - 0.3 cm = 1.5 cm
<h3>Part C</h3>
Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.
- V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
- V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³
<u>Total sand in the bottom part:</u>
<u>Time taken:</u>
- 12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds
Answer:
at least 20 rows.
Step-by-step explanation:
when you add the students, teachers, and chaperones, it comes to 159. then you divide 159 by the number of seats each row has, so 159/8 = 19.875, you would have to round to the nearest whole number so 20 should be correct.
Answer:
The answer is 234
Step-by-step explanation: