Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
Answer:
add 1;6 and 6,2 hope this helps ;)
To do this we need to move 10 to other side. To accomplish this you just need to add 10 to both side since (-10)
so
A+ 10 = c -10 + 10
we get
A+ 10 = c
lets say it wasn't -10 but positive 10.
A = c + 10 then we would subtract 10 from both sides
A -10 = c + 10 - 10
we get
A - 10 = C
<span>1. take English and niether of the other two?
</span>36-6 that we know take all 3
This leave 30.
Subtract the 6 from those taking history and English. Leaves 10.
Subtract the 10 from those taking English.
This leaves 20.
Subtract the 6 from those taking political science and English. Leaves 8.
Subtract 8 from those taking English.
Leaves 12
<span>
2. take none of the three courses? </span>
<span>
3. take history, but niether of the other two
</span>Do the same with history as we did with English.
32-6 = 26 -10=16-10=6
<span>
4. take political science and history but not english
</span>16-6 (that take all 3) = 10
Hope at least the partial answer helps!
