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Sedaia [141]
3 years ago
7

Help Please 15 points

Mathematics
2 answers:
dmitriy555 [2]3 years ago
5 0

Answer:

4\,x^5+x^3+2x^2-3\\ which is option (c)

Step-by-step explanation:

The standard form of a polynomial involves writing its terms in decreasing order of their degree. That is: the terms with larger degree are written first, and followed by the terms with lower degree.

In this case the terms of the polynomial are:

2\,x^2\,,\, x^3\,,\,-3\,,\, and \, 4\,x^5

Therefore, the term with largest degree (larger power of x) is 4\,x^5 (its degree is "5" because the power in the variable x is 5)

the following term according to its degree should be: x^3 (its degree is "3" because the power in the variable x is 3)

the next one is 2\,x^2 (its degree is "2" because the power in the variable x is 2)

the last term is the constant term "-3" (with degree zero since the variable x does not appear in it)

Therefore the standard form of the polynomial comes from rearranging the terms in decreasing order of their degrees as:

4\,x^5+x^3+2x^2-3\\

Tpy6a [65]3 years ago
3 0

Answer:

The Answer is c: 4x5 + x3 + 2x2 – 3

Step-by-step explanation:

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Which statements are correct? Check all that apply. A chord is sometimes a radius. A diameter is always a chord. A tangent is ne
katrin2010 [14]
1. (false) A chord is never a radius. A chord is the line segment whose 2 endpoints are points on the circle.

2. (true) A diameter is always a chord, in fact, it is the chord of largest length.

3. (true) A tangent is a line in the exterior of a circle, with only 1 common point with a circle. Whereas a secant has 2 common point with a circle and many more in the interior of the circle

4. (false) A chord can be at most equal to the length of the diameter.

5. (true) A chord can be very short. Consider 2 points on the circle which are very close to each other and the chord formed by them.

6. (true)  
7 0
3 years ago
Read 2 more answers
SOMEONE, PLEASE HELP!!!!!!
andrezito [222]

Answer:

I think its y^-3

Step-by-step explanation:

Since y^-3/y^-2 are both negatives they would swap places to become positive - y^2/y^3

then using rules of exponents you would subtract the exponents witch would be y^-3

7 0
3 years ago
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AWARDING DOUBLE POINTS question in pic, will report anything other than the answer
mash [69]

Answer:

m∠R is 72°

Step-by-step explanation:

In the given figure

∵ ΔPQR ≅ ΔUVW

→ From congruency

∵ m∠P = m∠U

∵ m∠Q = m∠V

∴ m∠R = m∠W

∵ m∠R = (10x - 18)°

∵ m∠W = 8x°

∵ m∠R = m∠W

→ Equate their measures

∴ 10x - 18 = 8x

→ Add 18 to both sides

∵ 10x - 18 + 18 = 8x + 18

∴ 10x = 8x + 18

→ Subtract 8x from both sides

∴ 10x - 8x = 8x - 8x + 18

∴ 2x = 18

→ Divide both sides by 2 to find x

∴ x = 9

→ Substitute the value of x in the m∠R

∵ m∠R = 10(9) - 18

∴ m∠R = 90 - 18

∴ m∠R = 72°

∴ m∠R is 72°

7 0
3 years ago
John has a rectangular-shaped field whose length is 62.5 yards and width is 45.3 yards. The area of the field is ________ square
oee [108]
Area = 2831.25 square yards

Perimeter =215.6 yards

EXPLANATION

The area and perimeter of a rectangular field are found using the formula for finding the area and perimeter of a rectangle respectively.

That means, area of the rectangular field is given by the formula,

A= l\times w

We just have to substitute
l=62.5 and w= 45.3 into the given formula and evaluate.

This implies that;

A= 62.5\times 45.3

This gives the area of the rectangular-shaped field to be;

A= 2831.25 square yards.

Now for the perimeter, we use the formula

P=2w +2l

Or

P=2(w +l)

Substituting the values for the length and width gives,

P=2(62.5+45.3)

\Rightarrow P=2(107.8)

\Rightarrow P=215.6

Hence the perimeter of the rectangular shaped field is 215.6 yards.
8 0
3 years ago
Solve for x: 16 = x + 32
RideAnS [48]

Answer:

-16

Step-by-step explanation:

Use everyone's favourite thing: ALGEBRA!!!

16=x+32

16-32=x

-16=x

Hope that helps

6 0
3 years ago
Read 2 more answers
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