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riadik2000 [5.3K]
2 years ago
12

For the reaction H₂O(g) + Cl₂O(g) → 2HClO(g), you know ΔS°rxn and S° of HClO(g) and of H₂O(g). Write an expression that can be u

sed to determine S° of Cl₂O(g).
Chemistry
1 answer:
expeople1 [14]2 years ago
6 0

The expression for  S°(Cl2O)(g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Given ,

The balanced chemical equation is ,

H2O (g) + Cl2O (g) → 2HClO (g)

The general standard entropy of the reaction is given by ,

ΔS°rxn = sum of the S°(Product ) - sum of the S°(reactants )

ΔS°rxn = ΣmS°products  -  ΣnS°reactants

where , m and n are the stoichiometry coefficients of each product and reactants .

Thus , the standard entropy of the given reaction is given by ,

ΔS°rxn = 2×S° (HClO)(g)  - [ S°(H2O)(g) + S°(Cl2O)(g) ]

ΔS°rxn = 2×S° (HClO)(g) - S°(H2O)(g) - S°(Cl2O)(g)

Thus the S°(Cl2O) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Hence the expression for the standard entropy of Cl2O (g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

<h3>What is a balance chemical reaction ?</h3>

A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .

Learn more about chemical reaction here :

brainly.com/question/1893305

#SPJ4

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Answer:

The answer is given below

Explanation:

When electronegativity difference arises between the bonded atoms, then a molecule is polar.

When electros are shared equally between the bonded atoms or when the polar bonds in a bigger molecule cancels out each other, then a a molucule is non polar.

(a) 50% isopropanol/H2O,--- 2 (second least polar)

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3 years ago
1. If we have a reaction of Zn3PO4 and HCl, what would the products of this
Vladimir79 [104]

Answer:

1. The products of this reaction are ZnCl₂ and H₃PO₄.

2. 14.57 g.

Explanation:

<em>1. What would the products of this  reaction be?</em>

  • The balanced reaction between Zn₃(PO₄)₂ and HCl is represented as:

<em>Zn₃(PO₄)₂ + 6HCl → 3ZnCl₂ + 2H₃PO₄,</em>

It is clear that 1.0 mol of Zn₃(PO₄)₂ reacts with 6.0 mol of HCl to produce 3.0 mol of ZnCl₂ and 2.0 mol of H₃PO₄.

So, the products of this reaction are ZnCl₂ and H₃PO₄.

<em>2. If we produced 13.05 g of H₃PO₄, how many grams of  hydrochloric acid would be need to start with?​</em>

  • Firstly, we should get the no. of moles (n) of 13.05 grams of H₃PO₄:

n = mass/molar mass = (13.05 g)/(97.994 g/mol) = 0.1332 mol.

<u><em>Using cross-multiplication:</em></u>

6.0 mol of HCl needed to produce → 2.0 mol of H₃PO₄, from stichiometry.

??? mol of HCl needed to produce → 0.1332 mol of H₃PO₄.

∴ The no. of moles of HCl needed = (6.0 mol)(0.1332 mol)/(2.0 mol) = 0.3995 mol.

∴ The mass of HCl needed = n*molar mass = (0.3995 mol)(36.46 g/mol) = 14.57 g.

<em>So, the grams of  hydrochloric acid would be need to start with = 14.57 g.</em>

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