Answer:
Benzoic acid
Explanation:
The strength of an acid is principally a measure of its dissociative capabilities in aqueous solutions. While strong acids dissociate completely in solution, weak acids dissociates only partially.
The relative strength of an acid can be obtained from its pKa value. The pKa value is the negative logarithm of the concentration of the Ka value.
Stronger acids have a pKa value usually negative. This is a pointer to the fact that the lower the pKa value, the stronger the strength of the acid in question.
Relatively therefore, Benzoic acid is stronger than acetic acid because it has a lesser value for pKa
Try this solution:
if 1 mole is 55.8 gr., then 2.25 moles the mass should be 55.8*2.25=125.55 gr.
Answer: 125.55 gr.
Answer and Explanation:
The IUPAC substitutive name of the major product when 2-methylbut-1-ene reacts are as follows
a) HCl = 2-chloro-2-methylbutane
b) HBr in the presence of peroxides = 1-bromo-2-methylbutane
c) H2O/ H2SO4 (dilute sulfuric acid) = 2-methylbutane-1,2-diol
d)BH3-THF followed by basic hydrogen peroxide = 2-methylbutan-1-ol
e) Chlorine in water = 2-chloro-2-methylbut -1 -ol
f) Bromine in carbon tetrachloride = 1,2- dibromo-2-methybutane
g) H2 in the presence of a metal catalys = isopentane or 2- methyl butane
Answer:
1 litre of 1.0 M NaCl
Explanation:
When an ionic compound dissolves in water, it dissociates into ions. Consider the dissolution of sodium chloride in water;
NaCl(s) ------> Na^+(aq) + Cl^-(aq)
Hence, two solute particles are obtained from each formula unit of NaCl, a greater concentration of NaCl will contain a greater number of sodium an chloride ion particles.
Glucose is a molecular substance and does not dissociate in solution hence it yields a lesser number of particles in solution even at the same concentration as NaCl
