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stiks02 [169]
2 years ago
6

Solution a has a hydrogen ion concentration of 3. 2 x 10-9 and solution b has a hydrogen ion concentration of 6. 9 x 10-5. Which

solution is more basic?.
Chemistry
1 answer:
Tatiana [17]2 years ago
8 0

Solution a is more basic.

Basic solutions are those solutions whose pH is greater than 7.

The pH of a solution is calculated or determined by the hydrogen ion concentration of the solution. The relation between pH of a solution and the hydrogen ion concentration in it is given by :

pH = -log[ H+]

From this relation we can conclude that if the hydrogen ions concentration in a solution is more , the value of pH will become lower.

For Solution a, the pH is given by :

pH(a) = -log [ 3.2 x 10^-9 ] = 8.4948 ≅ 8.5

For Solution b, the pH is given by :

pH(b) = -log [ 9 x 10^-5 ] = 4.04 ≅ 4

Since the pH of solution b is lower than the pH of solution a , solution a is more basic than solution b. Moreover, the pH of solution a is approximately 8.5 which makes it a moderately strong basic solution.

(To know more about pH : brainly.com/question/1542454 )

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480.40 g.

Explanation:

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<em>2 SO₂(g) + O₂(g) → 2 SO₃(g),</em>

it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.

  • We can get the no. of moles of SO₃ produced:

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∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.

  • Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:

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What is the role of the fungus in the food web shown?
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Answer:

0.535 g

Explanation:

The reaction that takes place is:

  • NaCl + AgNO₃ → AgCl + NaNO₃

First we <u>calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution</u>, using the <em>definition of molarity</em>:

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  • moles = Molarity * liters

<em>Converting 25.0 mL to L </em>⇒ 25.0 / 1000 = 0.025 L

  • moles = 0.366 M * 0.025 L = 0.00915 mol AgNO₃

Then we <u>convert AgNO₃ moles into NaCl moles</u>:

  • 0.00915 mol AgNO₃ * \frac{1molNaCl}{1molAgNO_3} = 0.00915 mol NaCl

Finally we<u> convert NaCl moles into grams</u>, using its <em>molar mass</em>:

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Answer:

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