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Ainat [17]
3 years ago
7

Which of the following best explains why bonds form between atoms?

Chemistry
1 answer:
ANEK [815]3 years ago
6 0

Answer:

D

Explanation:

I believe the answer is D because atoms are always seeking to fill up their outer electron shell/valence shell and want to gain a full octet.

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What is the energy in joules of one photon of<br> microwaveradiation with a wavelength 0.122m?
pentagon [3]

<u>Answer:</u> The energy of photon is 162.93\times 10^{-26}J

<u>Explanation:</u>

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = energy of the light  = ?

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of photon = 0.122 m

Putting values in above equation, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{0.122m}\\\\E=162.93\times 10^{-26}J

Hence, the energy of photon is 162.93\times 10^{-26}J

3 0
3 years ago
Draw a mechanism for this reaction. 5-hydroxypentanoic acid forms 2-oxanone in the presence of acid. draw all missing reactants
Licemer1 [7]

Answer: -

The first step involves protonation of the carbonyl oxygen.

After protonation, the Alcohol oxygen now attacks the carbon of the carbonyl.

Thus a six membered ring is formed with 5 carbon atoms and 1 oxygen atom. The 1st position carbon atom has 2 OH groups.

One of these gets again protonated.

This leaves as water. With the loss of the H+, there results a carbonyl at 1 position.

Thus 5-hydroxypentanoic acid forms a lactone or 2-oxanone in presence of acid.

3 0
3 years ago
Consider a transition of the electron in the hydrogen atom from n=5 to n=9. Determine the wavelength of light that is associated
lesantik [10]
Lol i need to answer more and plus n could also = # 4.65
5 0
4 years ago
¿Cuál de las siguientes configuraciones globales corresponde a un elemento químico que se comporta como metal? 1 punto [He]2s2 2
yuradex [85]

Answer:

[Ne]3s2

Explanation:

ahora tenemos que mirar cada una de las configuraciones electrónicas de cada átomo de cerca antes de tomar una decisión.

considerando la configuración electrónica más externa de cada una de las especies mostradas;

para la primera configuración, ns2 np6 corresponde a un gas noble.

para la segunda configuración ns2 np3 corresponde a un elemento no metálico del grupo 5.

para la tercera configuración, ns2 corresponde a un elemento metálico del grupo 2.

para la cuarta configuración, ns2 np4 corresponde a un elemento no metálico del grupo 6

5 0
3 years ago
Please help its difficult
Likurg_2 [28]

Answer:

pounds

pounds pounds pounds

8 0
3 years ago
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