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2 years ago

What is the decimal form of the following binary ip address? 11001101.00111001.10101001.01000010

Computers and Technology

1 answer:

jasenka [17]2 years ago

3 0

The decimal form of the 11001101.00111001.10101001.01000010 binary ip address is 205.57.169.66.

An IP address is a binary number with 32 bits. The 32 bits are divided into four octets, which are groupings of 8 bits each. An IP address, however, is shown as a dotted decimal number (for example: 205.57. 32.9).

Memory regions are given binary addresses by the computer system. But in order to access a memory location, the system utilises a certain number of bits. We can address two memory regions with 1 bit. We can address 4 memory locations with 2 bits and 8 memory locations with 3 bits.

The 4 sets of 8 bits in each of the 4 directions are simply written down to create the 32-bit binary IP address.

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3 years ago

What kind of loop repeats until something else (determined by the program) happens?

VLD [36.1K]

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3 years ago

Read 2 more answers

A computer has a cache and main memory. 20 ns are required to reference a word that is in the cache. If the word is in main memo

Alecsey [184]

Answer:

$T_{average} =12026ns$

Explanation:

Given Information:

$T_{cache}=20 ns$

$T_{main}=60ns$

$T_{disk} =12ms=12,000,000ns$

$hit_{cache} =0.9$

$miss_{cache} =1-0.9=0.10$

$hit_{main} =0.99$

$miss_{main} =1-0.99=0.01$

There are 3 possible cases

1. Location of reference word is in cache

$T_{cache}*hit_{cache} =20*0.9=18ns$

2. Location of reference word is not in cache but in main memory

$(T_{cache}+T_{main})*(miss_{cache}*hit_{main}) =(20+60)*(0.10*0.99)=7.92ns$

3. Location of reference word is neither in cache nor in main memory

$(T_{cache}+T_{main}+T_{disk})*(miss_{cache}*miss_{main})$

$(20+60+12,000,000)*(0.10*0.01)=12000.08 ns$

The average time required to access a referenced word on this system is simply the sum of above 3 cases

$T_{average} =18+7.92+12000.08=12026ns$

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3 years ago

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If the word size was 16 bit. The answer would be 128 KB.

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3 years ago

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Kruka [31]

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3 years ago