The final velocity of the passenger is zero as he is brought to rest by the inflated bag.
Apply the equation of motion
Replacing with our values,
Calculate the force using the force equation,
Therefore the magnitude of force acts on the passenger's upper torso is 34.923kN
You just told us that Weight = (mass) x (gravity),
and that mass=10kg and gravity = 9.8 m/s².
All we need to do is write those numbers in place of the letters.
Weight = (10 kg) x (9.8 m/s²) = <em>98 newtons</em>.
Answer:
<h2>E. 650N</h2>
Explanation:
step one:
given
length of stretcher= 2m
weight of stretcher=100N
Wayne weighs =800N
distance of Wayne weighs from chris's end= 75cm= 0.75m
The force that Chris is exerting to support the stretcher, with Wayne on it, can be computed by taking moments of the weight of the stretcher and Wayne weighs about Chris's end, the end result is the reaction at Chris's end
Taking moment about Chris's end
The moment of Wayne weight 75cm from Chris+ Half the weight of stretcher 1m from Chris
0.75*800+50*1=0
600+50=0
650N
Answer:
This question is incomplete
Explanation:
The question is incomplete. However, to determine the time (in seconds) it took a worker to hit the ground from an elevated point. The speed the worker was coming with to the ground and the distance between the elevated point and the ground will have to be considered. Thus the formula to be used here will be
Speed (in meter per second) = distance (in meters) ÷ time (in seconds)
time (in seconds) = distance (in meters) ÷ speed (in meter per seconds)
