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Naddika [18.5K]
2 years ago
11

Our school needs to offer healthier options in the lunchroom. Elever High School has recently updated its cafeteria menu to incl

ude whole wheat pasta and breads, a fresh salad bar, and other healthy menu items. Students there claim that they have more energy and focus throughout their school day. Let's encourage healthier menus in our lunchroom!
What type of evidence does the writer of this passage use to support her claim?


statistics
statistics

an expert's opinion
an expert's opinion

examples
examples

the writer's opinion
Physics
1 answer:
White raven [17]2 years ago
6 0

Answer:

b

Explanation:

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Which sentence best explains the difference between potential energy and
yan [13]

Answer:

C. Potential energy is related to an object's position, and kinetic

Explanation:

The energy contained in the small motions of the object's molecules can be broken up into a combination of microscopic kinetic energy and potential energy.

6 0
2 years ago
What are the two factors that determine a material's density?
Juliette [100K]
Mass and volume are the 2 factors to determine density
3 0
3 years ago
A football player, with a mass of 69.0 kg, slides on the ground after being knocked down. At the start of the slide, the player
White raven [17]

Answer:

(a) -472.305  J

(b) 1 m

Explanation:

(a)

Change in mechanical energy equals change in kinetic energy

Kinetic energy is given by0.5mv^{2}

Initial kinetic energy is 0.5\times 69\times 3.7^{2}=472.305 J

Since he finally comes to rest, final kinetic energy is zero because the final velocity is zero

Change in kinetic energy is given by final kinetic energy- initial kinetic energy hence

0-472.305  J=-472.305  J

(b)

From fundamental kinematic equation

v^{2}=u^{2}+2as

Where v and u are final and initial velocities respectively, a is acceleration, s is distance

Making s the subject we obtain

s=\frac {v^{2}-u^{2}}{-2a} but a=\mu g hence

s=\frac {v^{2}-u^{2}}{-2\mu g}=\frac {0^{2}-3.7^{2}}{-2*0.7*9.81}=0.996796272\approx 1 m

7 0
3 years ago
Evaluate the use of hydrogen as a fuel. Explain how hydrogen is produced. Write about the environmental impact of using diesel a
nadya68 [22]

Explanation:

hydrogen is primarily produce by steam reforming of natural gas... Methane reacts with steam under 3 -25 bar pressure in the presence of a catalyst to "Produce Hydrogen " , carbon monoxide, and the greenhouse gas carbon dioxide. For steam to proceed, heat must be supplied to the process. Furthermore , new research from Transport & Environment shows that diesel cars not only pollute the air but also emit more climate change emissions (co2) than petroleum gas cars whenever compared to diesel fueled vehicles lifetime. In fact, diesel engines emits 3.65 tonnes of co2 more than a petrol engine equivalent.

6 0
3 years ago
You pull on a spring whose spring constant is 22 N/m, and stretch it from its equilibrium length of 0.3 m to a length of 0.7 m.
Liono4ka [1.6K]

Answer:

W= 4.4 J

Explanation

Elastic potential energy theory

If we have a spring of constant K to which a force F that produces a Δx deformation is applied, we apply Hooke's law:

F=K*x  Formula (1): The force F applied to the spring is proportional to the deformation x of the spring.

As the force is variable to calculate the work we define an average force

F_{a} =\frac{F_{f}+F_{i}  }{2}  Formula (2)

Ff: final force

Fi: initial force

The work done on the spring is :

W = Fa*Δx

Fa : average force

Δx :  displacement

W = F_{a} (x_{f} -x_{i} )   :Formula (3)

x_{f} :  final deformation

x_{i}  :initial deformation

Problem development

We calculate Ff and Fi , applying formula (1) :

F_{f} = K*x_{f} =22\frac{N}{m} *0.7m =15.4N

F_{i} = K*x_{i} =22\frac{N}{m} *0.3m =6.6N

We calculate average force applying formula (2):

F_{a} =\frac{15.4N+6.2N}{2} = 11 N

We calculate the work done on the spring  applying formula (3) :         :

W= 11N*(0.7m-0.3m) = 11N*0.4m=4.4 N*m = 4.4 Joule = 4.4 J

Work done in stages

Work is the change of elastic potential energy (ΔEp)

W=ΔEp

ΔEp= Epf-Epi

Epf= final potential energy

Epi=initial potential energy

E_{pf} =\frac{1}{2} *k*x_{f}^{2}

E_{pi} =\frac{1}{2} *k*x_{i}^{2}

E_{pf} =\frac{1}{2} *22*0.7^{2} = 5.39 J

E_{pf} =\frac{1}{2} *22*0.3^{2} = 0.99 J

W=ΔEp=  5.39 J-0.99 J = 4.4J

:

4 0
2 years ago
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