Answer:
The minimum thickness of the film and the wavelength of the light in air are 
and 371 nm.
Explanation:
Given that,
Refractive index of soap= 1.34
Refractive index of glass= 1.55
Wavelength = 642 nm
(I). We need to calculate the minimum thickness
Using formula of thickness
Where, m = 0 for constrictive
Put the value into the formula
(II). We need to calculate the wavelength
Using formula of wavelength
Where, m = 1
Put the value into the formula
Hence, The minimum thickness of the film and the wavelength of the light in air are and 371 nm.
Answer:
A 0.17 kg baseball is launched from the roof of a building 14 m above the ground. Its initial velocity is 29 m/s at 40° above the horizontal. Assume any effects of air resistance are negligible.
(a) What is the maximum height above the ground that the ball reaches?
m
(b) What is the speed of the ball as it strikes the ground?
m/s
The Earth's core is estimated to be bigger than both Mars and Mercury. However, I would say that Mercury is the safest choice. Mercury is also known to be smaller than Jupiter's Moon!
Answer:
F = 29.64 × 10-¹¹N
Explanation:
From newton's law of gravitation which states that every object in the universe will attract each other with a force which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.
That is, F = (Gm1m2)/ r²
From the question m1=4kg, m2 = 2.5kg, r= 1.5m,G = 6.67×10-¹¹
F=( 6.67×10-¹¹ × 4 × 2.5) / 1.5²
F = (66.7×10-¹¹) / 2.25
F = 66.7/2.25 × 10-¹¹ N
F = 29.64 × 10-¹¹N
F = 29.64 × 10-¹¹N
I hope this was helpful, please mark as brainliest
Answer:
The speed should be reduced by 1/√2 or 0.707 times
Explanation:
The relationship between the kinetic energy, mass and velocity can be represented by the following equation:
K.E = ½m.v²
In this equation, the mass is inversely proportional to the square of the velocity or speed. This means that as the mass increases, the speed reduces by × 2.
Let; initial mass = m1
Final mass = m2
Initial velocity = v1
Final velocity = v2
According to the question, if the mass of the body is doubled i.e. m2 = 2m
½m1v1² = ½m2v2²
½ × m × v1² = ½ × 2m × v2²
Multiply both sides by 2
(½ × m × v1²)2 = (½ × 2m × v2²)2
m × v1² = 2m × v2²
Divide both sides by m
v1² = 2v2²
Divide both sides by 2
v1²/2= v2²
Square root both sides
√v1²/2= √v2²
v1/√2 = v2
v2 = 1/√2 v1
This shows that to maintain the same kinetic energy if the mass is doubled, the speed should be reduced by 1/√2 or 0.707 times.
