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Kitty [74]
3 years ago
7

What type of material can charges move through easily?

Physics
1 answer:
Katyanochek1 [597]3 years ago
4 0
Pass through it easily is called a Metals such as iron, steel, copper, and aluminum are good conductors.
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The pulse site located at the point where the upper leg bends is called the femoral. It is an artery found in the thigh. It is large and is deemed as the main arterial supply for the lower part of the body. It is known as the second artery that is the largest. It is being used as the catheter access artery. From it, diagnostics for the heart, brain, arms, kidney and other parts can be directed to the other arterial system. It can also be used as a source to draw blood that is from the arteries when there is low blood pressure.
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3 years ago
For both resonance curves and Fourier spectra, amplitude is plotted vs frequency, but these two types of plots are not the same.
andrey2020 [161]

Answer:

he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.

Explanation:

In a resonance experiment, the amplitude of the system is plotted as a function of the frequency, finding maximums for the values ​​where some natural frequency of the system coincides with the excitation frequency.

In a Fourier transform spectrum, the amplitude of the frequencies present is the signal, whereby each peak corresponds to a natural frequency of the system.

From this explanation we can see that in the first case the peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.

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3 years ago
What do slinky waves and seismic waves have in common? A. They both always occur as transverse waves. B. They both always occur
Usimov [2.4K]

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3 years ago
Read 2 more answers
(a) Calculate the magnitude of the gravitational force exerted on a 497-kg satellite that is a distance of 1.92 earth radii from
Setler [38]

Answer:

a)  1321.45 N

b)  1321.45 N

c)  2.66 m/s^2

d) 2.21*10^-22 m/s^2

Explanation:

Hello!

First of all, we need to remember the gravitational law:

F = G \frac{m_1 m_2}{r^2}

Were

   G = 6.67428*10^-11 N(m/kg)^2

   m1 and m2 are the masses of the objects

   r is the distance between the objects.

In the present case

m1 = earth's mass =  5.9742*10^24 kg

m2 = 497 kg

r = 1.92 earth radii = 1.92 * (6378140 m) = 1.2246*10^7 m

Replacing all these values on the gravitational law, we get:

F = 1321.45 N

a)  and  b)

Both bodies will feel a force with the same magnitude 1321.45 N but directed in opposite directions.

The acceleration can be calculated dividing the force by the mass of the object

c)

a_satellite = F/m_satellite = ( 1321.45 N)/(497 kg)

a_satellite = 2.66 m/s^2

d)

a_earth = F/earth's mass = (1321.45 N)/( 5.9742*10^24 kg)

a_earth = 2.21*10^-22 m/s^2

8 0
3 years ago
What force is required to give an object with mass 300 kg an acceleration of 2
Andre45 [30]

Answer:

C. 600 N

Explanation:

Given,

mass of object (m)= 300kg

acceleration(a) =2m/s^2

We know that,

Force(F)=ma

=300*2

=600N

So,600N force is required to give an object.

5 0
3 years ago
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