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3 years ago

Which of the following statements about atoms is NOT true?

Chemistry

1 answer:

Alika [10]3 years ago

6 0

Answer:

atoms are too small to be seen under a microscope

Explanation:

scientists have been always making research on atomic structure which cannot be directly looked through a microscope

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Look at the chemical equation:

zhuklara [117]

Answer:

The correct answer is 6 i believe

Explanation:

6 would be on both sides on H while balancing the equation 2 would be for N

4 0

4 years ago

A 1 l container contains O2 gas at stp. if the diameter of the O2 molecule is 3.75 * 10^-10 m the mean free path of the o2 molec

Luba_88 [7]

The mean free path of the O₂ molecule is $5.97*10^{-5}$ m.

The mean free path of the O₂ molecule is calculated by the formula -

λ = $\frac{1}{\sqrt{2}*\pi *d^{2}*n}$

In this formula, λ represents mean free path of gas, d represents diameter and n is number of molecules.

As per the known fact, 1 mole of gas occupies 22.4 liter at STP.

So. 1 liter of O₂ gas will have number of moles = $\frac{1*1}{22.4}$

Number of moles = 0.045

Also, we are aware that 1 mole contains $6.02*10^{23}$ molecules.

So, 0.045 moles will contain number of molecules = $6.02*10^{23}*0.045$

Number of molecules = $2.7*10^{22}$ molecules

Now, keeping the values in formula to find mean free path of gas -

λ = $\frac{1}{1.4*3.14*(3.75*10^{-10})^{2} *2.7*10^{22} }$

λ = $\frac{1}{16746.7}$

λ = $5.97*10^{-5}$ m

Hence, the mean free path of the O₂ molecule is $5.97*10^{-5}$ m.

Learn more about calculation of mean free path -

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8 0

2 years ago

Convert the following Grams: 0.200 moles of H2S

ANEK [815]

Answer:

6.82 g H₂S

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

0.200 mol H₂S

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

Step 3: Convert

Set up: $\displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})$
Multiply: $\displaystyle 6.818 \ g \ H_2S$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

6.818 g H₂S ≈ 6.82 g H₂S

7 0

3 years ago

20 mL of NaOH solution was added to the conical flask. Indicator was added & titrated with 0.1 M HCl solution. The HCl used

svlad2 [7]

Answer:

[NaOH] = 0.1 Molar ... Note => the brackets around formula;i.e., "[ ]" is generally accepted in the chemistry community as concentration in Molar terms.

Explanation:

The metathesis rxn, or double replacement rxn, equation is:

(Molarity x Volume) of acid = (Molarity x Volume) of base, or

(M·V)acid = (M·V)base => M(base) = M·V(acid)/V(base)

= 0.1M × 18.3ml / 20ml = 0.0915M(base) = 0.1M (1 sig-fig) = [NaOH]

8 0

3 years ago

Consider the following system at equilibrium where H° = 16.1 kJ, and Kc = 6.50×10-3, at 298 K. 2NOBr(g) 2NO(g) + Br2(g)If the VO

Norma-Jean [14]

Answer:

1) The value of Kc : (C.) remains the same

2) The value of Qc : (A.) is greater than Kc

3) The reaction must : (B.) run in the reverse direction to reestablish equilibrium.

4) The number of moles of Br2 will : (B.) decrease

Explanation:

Value of concentration equilibrium constant Kc depends only on temperature. Since temperature remains constant, therefore, Kc remains constant. Decrease in volume means increase in pressure. Increase in pressure favors the side with less gaseous species. Hence, increase in pressure will favor the reverse reaction towards reactants.

7 0

3 years ago