(10.0 g Al2(SO3)3) / (294.1544 g Al2(SO3)3/mol) = 0.033996 mol Al2(SO3)3 (10.0 g NaOH) / (39.99715 g NaOH/mol) = 0.25002 mol NaOH
0.033996 mole of Al2(SO3)3 would react completely with 0.033996 x (6/1) = 0.203976 mole of NaOH, but there is more NaOH present than that, so NaOH is in excess and Al2(SO3)3 is the limiting reactant.
The empirical formula of this compound is equal to
.
<h3>
Empirical formula</h3>
To calculate the empirical formula of a compound, it is necessary to know the number of moles present.
Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:






Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values by the smallest common factor to transform into an integer, so that:
O => 
Fe => 
So, the empirical formula of this compound is equal to 
Learn more about empirical formula in: brainly.com/question/1363167
Answer:
Original volume=3L
Explanation:
Assuming the gas in the ballon is ideal and the temperature does not vary with height we have the gas law as
PV=nRT
Here RHS is constant in both the conditions which means
PV=constant
Given P1=1 atm V1=V P2=0.75atm V2=4L
P1V1=P2V2

V=3L
The initial volume of the gas is 3L
Answer:
Because DNA is like a code for an organism such as sheep or humans the code of gene segments such as C G A T all collaborate and make a strand of DNA so it all depends on the letters our parents traits and the enviroment.
Explanation:
Hope this helps