1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleks04 [339]
2 years ago
7

How does voltage work in a circuit?​

Chemistry
1 answer:
PIT_PIT [208]2 years ago
3 0

Answer:

Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Explanation:

I hope this is right i found it off a website called fluke!

You might be interested in
A mixture containing initially 3.90 mole of NO(g) and 0.88 mole of CO2(g) was allowed to react in a flask of volume 1.00 L at a
Ymorist [56]

Answer:

Equilibrium constant Kc for the reaction will be 1.722

Explanation:

O2(g)+NO(g)→CO(g)+ NO2(g)

0.88    3.9        ---         ---

0.88x   3.9-x     x           x

GIVEN:

0.88X-X= 0.11

⇒ X=0.77

CO2(g)+NO(g) → CO(g) + NO2(g)

0.88       3.9         ---          ---

0.88-x    3.9-x      x            x

=              3.13       0.77      0.77

=0.11

Kc = \frac{[CO] *[NO2]} {[CO2]*[NO]}

     ={{0.77}×0.77÷{{0.11×3.13}}

     = 1.722

6 0
3 years ago
Many portable gas heaters and grills use propane, C3H8(g). Using enthalpies of formation, calculate the quantity of heat produce
Elodia [21]

Answer:  600 kJ

-

Explanation:

                        C₃H₈ (g)  + 5 O₂ (g) =============== 3 CO₂ (g)  +  4 H₂O (l)

Δ⁰Hf   kJ/mol       -104             0                                       -393.5         -285.8

Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104)  kJ/mol

Δ⁰Hcomb = 2219.70 kJ/mol

n= m /MW   MW c₃H₈ = 44.1 g/mol

n= 12 g/44.1 g/mol = 0.27 mol

then for 12 g the heat released will be

0.27 mol x 2219.70 kJ/mol =  600 KJ

4 0
2 years ago
Read 2 more answers
If the molar heat of combustion of liquid benzene at constant volume and 300k is -3272KJ. Calculate the heat of combustion at co
vladimir2022 [97]

Answer:

The heat at constant pressure is -3,275.7413 kJ

Explanation:

The combustion equation is 2C₆H₆ (l) + 15O₂ (g)  → 12CO₂ (g) + 6H₂O (l)

\Delta n_g = (12 - 15)/2 = -3/2

We have;

\Delta H = \Delta U + \Delta n_g\cdot R\cdot T

Where R and T are constant, and ΔU is given we can write the relationship as follows;

H = U + \Delta n_g\cdot R\cdot T

Where;

H = The heat at constant pressure

U = The heat at constant volume = -3,272 kJ

\Delta n_g = The change in the number of gas molecules per mole

R = The universal gas constant = 8.314 J/(mol·K)

T = The temperature = 300 K

Therefore, we get;

H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ

The heat at constant pressure, H = -3,275.7413 kJ.

4 0
2 years ago
What is another word for the sound barrier?
8090 [49]

Answer:

The Answer is B. Destructive Interference

Explanation:

3 0
3 years ago
Read 2 more answers
Assume that you have a cylinder with a movable piston. What would happen to the gas pressure inside the cylinder if you do the f
pishuonlain [190]

Answer:

A. The pressure will increase 4 times. P₂ = 4 P₁

B. The pressure will decrease to half its value. P₂ = 0.5 P₁

C. The pressure will decrease to half its value. P₂ = 0.5 P₁

Explanation:

Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.

<em>What would happen to the gas pressure inside the cylinder if you do the following?</em>

<em />

<em>Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.</em>

V₂ = 0.25 V₁. According to Boyle's law,

P₁ . V₁ = P₂ . V₂

P₁ . V₁ = P₂ . 0.25 V₁

P₁ = P₂ . 0.25

P₂ = 4 P₁

<em>Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.</em>

T₂ = 0.5 T₁. According to Gay-Lussac's law,

\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}

<em>Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.</em>

n₂ = 0.5 n₁.

P₁ in terms of the ideal gas equation is:

P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}

P₂ in terms of the ideal gas equation is:

P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}

3 0
3 years ago
Other questions:
  • The amount of. moisture in the air is highest when relative humanity is
    14·1 answer
  • Calculate the solubility of silver chloride in 0.17M AgNO3. (Ksp=1.8E-10)
    6·1 answer
  • The common laboratory solvent ethanol is often used to purify substances dissolved in it. The vapor pressure of ethanol , CH3CH2
    13·1 answer
  • As electrons gain more energy they can move ____ away from the nucleus
    15·1 answer
  • What would happen to the population of an animal if its food source were removed from the food web
    11·1 answer
  • Find the block labeled ? in Figure 2. What is its atomic number? How many valence electrons does it have? Which of the elements
    15·2 answers
  • How many atoms are in 200.0 grams of Sulfur (S)?
    11·1 answer
  • What are the physical and chemical properties of iron oxide
    10·1 answer
  • A balloon is placed in a vacuum chamber (a container that all of the air can be pumped out of) and as the air is removed, the ba
    10·1 answer
  • 1. The maximum recommended amount of citric acid (H3C6H5O7; the 3 hydrogens listed first are the acidic hydrogens – the only hyd
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!