Answer:
yes, albert is better grffffrr#fffffrttt.
Explanation:
And also explosion tha is another type
Answer:
There is a mass of 154 Grams of Carbon Dioxide.
Explanation:
One mole is equal to 6.02 × 10^23 particles.
This means we have 1.05 X 10^24 total particles of Ethane.
Each ethane particle contains 2 carbon atoms.
If every particle of ethane is burned, we will end up with 2.10 x 10^24 molecules of Carbon Dioxide (Particles of Methane x 2, since each Methane particle contains 2 carbon atoms)
Carbon Dioxide has a molar mass of 44.01 g/mol
So if we take our amount of Carbon Dioxide molecules and divide it by 1 mole, ((2.10 x 10^24)/(6.02 x 10^23) = 3.49) we find that we have 3.49 moles of Carbon Dioxide.
Now all we need to do is multiply our moles of carbon dioxide(3.49) by it's molar mass(44.01) while accounting for significant digits.
What you should end up with is 154 Grams of Carbon Dioxide.
Hope this helps (And more importantly I hope I didn't make any errors in my math lol)
As a side note this is all assuming that this takes place at STP conditions.
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Molarity refers to moles/ L. This indicates the concentration of a solution containing solute and solvent.
1 molar solution contains 1 mole of solute in 1 L of solvent.
According to Avogadro's number, 1 mole of a substance contains 6.023 x 10^23 molecules, atoms, or ions.
For this reason, 6.023 x 10^23 atoms, ions, or molecules are in a molar solution.
