A research van de graaff generator has a 2.30 m diameter metal sphere with a charge of 1.10 mc on it. (a) what is the electric p
1 answer:
The potential on the surface of the charged sphere is 3.9 × 10⁷ volts.
Given:
The diameter of the sphere is 2.30 m and the charge of 1.10 mc.
The potential on the surface of a charged sphere is given by,
Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.
V = 8.99×10⁹×5×10⁻³/(2.30÷2)
V = 3.9 × 10⁷ volts
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gs = 0.6 m/s^2
Explanation:
Given data:
velocity = 12 m/s
height s = 12t -(1/2) g_s t^2
Given velocity is the derivatives of height
when velocity tend to 0 , maximum height is reached
at t = 20 sec ball reached the max height, so