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never [62]
2 years ago
9

A research van de graaff generator has a 2.30 m diameter metal sphere with a charge of 1.10 mc on it. (a) what is the electric p

otential on the surface of the sphere?
Physics
1 answer:
juin [17]2 years ago
7 0

The potential on the surface of the charged sphere is 3.9 × 10⁷ volts.

Given:

The diameter of the sphere is 2.30 m and the charge of 1.10 mc.

The potential on the surface of a charged sphere is given by,

V=k\frac{Q}{R}

Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.

V = 8.99×10⁹×5×10⁻³/(2.30÷2)

V = 3.9 × 10⁷ volts

To learn more about van de graaff generator: brainly.com/question/9987015

#SPJ4

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On Mars gravity is one-third that on Earth. What would be the mass on Mars of a person who has a mass of 90 kilograms (kg) on Ea
snow_tiger [21]

Answer: The person will still have a mass of 90kg on Mars

Explanation: The Truth is, the mass of a body remains constant from place to place. It is the weight which is equal to {mass of body * acceleration due to gravity{g}} that varies from place to place since it is dependent on {g}.

In this case the person will have a Weight of 90*9.8 = 882N on Earth.

{ "g" on Earth is 9.8m/s²}

And a Weight of 90*3.3 = 297N on Mars.

{ From the question "g" on Mars is {9.8m/s²}/3 which is 3.3m/s²}

From this analysis you notice that the WEIGHT of the person Varies but the MASS remained Constant at 90kg.

4 0
3 years ago
Which illustration represents low accuracy but high precision?​
Misha Larkins [42]

Answer:

D i think

Explanation:

7 0
3 years ago
Read 2 more answers
An object is placed 4.0 cm to the left of a convex lens with a focal length of +8.0 cm . Where is the image of the object?
Serjik [45]

The image of the object is 8cm to the left of the lens (D)

<h3></h3>

What is the image of an object?

The image of an object is said to be the location where light rays from that object intersect with a mirror by reflection.

It is calculated thus:

1÷v = 1÷f - 1÷u

<h3>How to calculate the image of an object</h3>

From the formula

1÷v = 1÷f - 1÷u

<h3>Where </h3>

V = image distance fromthe object

U = object

f = focal length

Substitute the values

1÷v = 1÷8 - 1÷ 4

1÷v = - 1÷8

Make v the subject of formula

v = -8cm

Therefore, the image of the object is 8cm to the left of the lens (D)

Learn more on focal length here:

brainly.com/question/25779311

#SPJ1

6 0
2 years ago
A 25kg object is 3.0 meters up. How much potential energy does it have
Anon25 [30]
GPE=mgh
=25 x 10 x 3
=750J
4 0
4 years ago
In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of th
Charra [1.4K]

Answer:

1960.32306 kg/s

Explanation:

m = Mass of water = 1 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height from which the water will fall

Potential Energy

PE=mgh\\\Rightarrow PE=1\times 9.81\times 52\\\Rightarrow PE=510.12\ J

One megawatts of power is required

So, flow rate

\dotm=\frac{P}{PE}\\\Rightarrow \dotm=\frac{1\times 10^6}{510.12}\\\Rightarrow \dotm=1960.32306\ kg/s

1960.32306 kg/s is required to produce a megawatt of power

7 0
3 years ago
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