3 years ago

When a tennis player practices by

Physics

1 answer:

WITCHER [35]3 years ago

7 0

Answer:

2nd bscause there is a reaction

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This problem has been solved!

lana66690 [7]

Answer:

Charge on each metal sphere will be $8\times 10^{8}C$

Explanation:

We have given number of electron added to metal sphere A $n=10^{12}electron$

As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.

So electron on both the spheres $=\frac{10^{12}}{2}=5\times 10^{11}electron$

We know that charge on each electron $e=1.6\times 10^{-19}C$

So charge on both the spheres will be equal to $q=1.6\times 10^{-19}\times 5\times 10^{11}=8\times 10^{8}C$

So charge on each metal sphere will be equal to $8\times 10^{8}C$

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What is required for force to come into play

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An interaction of one object with another object results in a force between the two objects. Thus, at-least two objects must interact for a force to come into play.

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