5x+2y2-y3:x=2 and y=4
5(2)+2(4)2-(4)3
10+8(2) -12
10+16-12
26-12
=14
Given
Rob is twice Joshua's age
Nick is 5 years older than Joshua.
sum of all their ages is 45.
Find the age of nick.
To proof
As given
Rob is twice Joshua's age
let Joshua's age = x
than Rob age = 2x
Nick is 5 years older than Joshua.
Nick age = 5 + x
sum of all their ages is 45
than the equation becomes
Joshua's age + Rob age + Nick age = 45
put the value
x + 2x + 5 + x = 45
4x = 40
x = 10
Joshua's age = 10 year
than Rob age = 20 year
Nick age = 5 + 10
= 15year
Hence proved
Because b^6 is present in both terms, we can factor it out.
b^6(7 + 12)
Combine like terms.
b^6(19)
Rearrange.
19b^6 is the fully simplified form of the given expression.
