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IRISSAK [1]
2 years ago
6

Petrina had a piece of red ribbon that measured 2.4 m long. she also had a piece of blue ribbon which was 7 8 m long. what was t

he total length of both ribbons? round your answer to 2 decimal places.
Mathematics
1 answer:
katen-ka-za [31]2 years ago
7 0

The total length of red and blue ribbons is 10.2 m.

Given that, the length of the red ribbon =2.4 m and the length of the blue ribbon =7.8 m.

<h3>How to add two decimals?</h3>

Adding decimals is similar to the usual addition of whole numbers. We know that a decimal number is a number with a whole number part and a fractional part which is separated by a decimal point.

Now, the length of the red ribbon + the length of the blue ribbon=2.4+7.8

=10.2 m

Therefore, the total length of red and blue ribbons is 10.2 m.

To learn more about the addition of decimals visit:

brainly.com/question/17612968.

#SPJ4

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Twenty of the 25 students in Mrs. Thigpen’s class are we wearing sneakers. What is the fraction in simplest form?
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Answer:

4/5

Step-by-step explanation:

20/25 = 4/5

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Which equation is represented by the table
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Answer:

B. b = 3a + 2

Step-by-step explanation:

We can write the equation in slope-intercept form as b = ma + c, where,

m = slope/rate of change

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✔️Find m using any two given pair of values, say (2, 8) and (4, 14):

Rate of change (m) = change in b/change in a

m = (14 - 8)/(4 - 2)

m = 6/2

m = 3

✔️Find c by substituting (a, b) = (2, 8) and m = 3 into b = ma + c. Thus:

8 = 3(2) + c

8 = 6 + c

8 - 6 = c

2 = c

c = 2

✔️Write the equation by substituting m = 3 and c = 2 into b = ma + c. Thus:

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Step-by-step explanation:

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The sum of two numbers is 196. One number is 64 more than the other. Find the numbers.
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Read 2 more answers
The table below shows the scores of a group of students on a 10-point quiz.Test ScoreFrequency3 54 15 16 27 28 49 310 1The mean
Katarina [22]

Explanation

Part A

We can use the formula below to find the mean.

\text{Mean}=\sum ^{}_{}(\frac{fx}{f})

We will then have;

\begin{gathered} \text{Mean = }\frac{5\times3+4\times1+5\times1+6\times2+7\times2+8\times4+9\times3+10\times1}{19}=\frac{15+4+5+12+14+32+27+10}{19} \\ =\frac{119}{19}=6.2632 \end{gathered}

Mean = 6.2632

Part B

Since the data set is odd.

\begin{gathered} \text{Median}=\frac{(n+1)}{2}^{th}\text{observation} \\ =\text{Value of }\frac{\text{(19+1)}}{2}^{th}\text{observation} \\ =\text{value of 10th observation} \end{gathered}

Answer: From the column of cumulative frequency cf, the median is 7

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1 year ago
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