8x^3 -5x^2 + 8x + 9+5x^3 + 3x^2 - 5x + 4 =
8x^3+5x^3-5x^2 + 3x^2+ 8x - 5x+ 9<span>+ 4 = </span>
13x^3-2x^2+3x+13
1/5 this shows that each can be picked up at Least 1/5 or 2/10
Answer:
its C
Step-by-step explanation:
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The sample mean is 
The sample size is n = 25
The standard deviation is 
Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table
From the question we are told the confidence level is 99.7% , hence the level of significance is
=>
Generally the degree of freedom is 
=> 
=>
Generally from the student t distribution table the critical value of
at a degree of freedom of
is
Generally the margin of error is mathematically represented as
=>
=>
Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as

=>
=>