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2 years ago

How does the pingpong ball's velocity before it collided with the can compare to its velocity after it collided with the can?

Physics

1 answer:

Arturiano [62]2 years ago

7 0

The velocity of before collision and after collision is equal and opposite.

<h3 /><h3>What is collision?</h3>

In physics, collision, which is also known as impact, is the abrupt, powerful coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer and a nail, two train carriages when linked, or a falling item and a floor.

If the collision is perfectly elastic , the momentum is conserved before and after collision . Therefore the velocity of before collision and after collision is equal and opposite.

to learn more about collision go to -

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A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00

Nutka1998 [239]

Answer:

$6.99535\times 10^{-6}\ V/m$

Explanation:

P = Power Output = 1000 W

r = Radius = 35000000 m

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

Intensity of Electric radiation is given by

$I=\dfrac{P}{A}\\\Rightarrow I=\dfrac{P}{4\pi r^2}\\\Rightarrow I=\dfrac{1000}{4\pi\times 35000000^2}\ W/m^2$

Intensity of Electric radiation is given by

$I=\dfrac{1}{2}c\epsilon_0E_0\\\Rightarrow E_0=\sqrt{\dfrac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\dfrac{2\times \dfrac{1000}{4\pi\times 35000000^2}}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=6.99535\times 10^{-6}\ V/m$

The amplitude of the electric field vector is $6.99535\times 10^{-6}\ V/m$

6 0

4 years ago

A beam of light traveling in air strikes a glass slab at an angle of incidence less than 90°. After entering the glass slab, wha

ad-work [718]

Answer:

True A and B

Explanation:

Let's propose the solution of the exercise before seeing the affirmations.

We use the law of refraction

n₁ sin θ₁ = n₂. Sin θ₂

Where n₁ and n₂ are the refractive indices of the two means, θ₁ and θ₂ are the angles of incidence and refraction, respectively

sin θ₂ = (n1 / n2) sin θ₁

Let's apply this equation to the case presented. The index of refraction and airs is 1 (n1 = 1)

Sin θ₂ = (1 / n2) sin θ₁

the angle θ₂ which is the refracted angle is less than the incident angle

Let's analyze the statements time

A. False. We saw that it deviates

B. True Approaches normal (vertical axis)

C. False It deviates, but it is not parallel to normal

D. False It deviates, but approaching the normal not moving away

E. True. Because its refractive index is higher than air,

8 0

3 years ago

A chemical reaction takes place in which energy is absorbed. Arrange the characteristics of the reaction in order from start to

myrzilka [38]

Let’s create a diagram that shows the chemical reaction absorb energy. Take a look at the diagram I created that is attached to this answer.

Now, the start of the graph line is pretty flat and low leveled. This is the start, which is the reactants. The beginning of a chemical reaction that absorbs energy will almost always start with reactants. I labeled this this “Start: Reactants” and colored the text light green so you can easily detect the part I’m talking about.

Moving on, we see there’s a light blue arrow pointing from the the near bottom to the top curve of the graph line. This is the where the activation energy is rising. Activation energy is the difference between the reactants and products. When the graph line begins to cure, this is when the transition state is beginning. I labeled the transition state, “Transition State” and colored the text a light orange. I colored the line a light blue and also labeled it “Activation Energy” and colored the text light blue as well. I hope it’s easy enough for you to follow along. :)

Next we see that the graph line dips and then goes flat, but it doesn’t go low leveled. It says fairly higher than where it started. This is the end product. I labeled this “End: Product” and colored the text light purple so you can easily detect it.

Okay, now that that’s clear, let’s go ahead and fill in the first blank. According to the diagram we see that the start should be a reactant, and since the graph line starts out pretty low. So, this means that the first tile should be “Low energy of reactants."

Now the second tile should definitely be “Transition State.” This is because the second part in the diagram is transition state. Again, this is mainly where the activation energy is starting to rise.

As for the last and final tile, we should chose “High energy of products.” This is because the diagram is left off on a high leveled part at the end of the graph line.

So, when you place the tiles they should look something like this.

Low energy of reactants

↓

Transition state

↓

High energy of products

- Marlon Nunez