Answer:
Explanation:
1. Select all the statements about the nucleus of the atom that are correct:
Group of answer choices
B. It contains Protons
D. It has a Positive Charge
E. It contains Neutrons
2. An atom of an element with atomic number 50 and mass number 120 contains:
Group of answer choices
B. 50 protons, 50 electrons, and 70 neutrons
3. Which of these statements is false?
Group of answer choices
D. Electrons have the same mass as a proton but have the opposite charge.
The water dissolves the salt because the water molecules are able to interact with the salt-forming particles, called ions. When the water Interacts with the trainers of the salt ions, the solid salt crystal structure Suffers breakdown, until the trainers of the salt ions are completely surrounded by water molecules. At this time the salt is fully dissolved by water.
hope this helps!
Answer:
2.99 atm
2279.43 torr
44.07 psi
Explanation:
Torr, atms and psi all units are units of pressure.
Conversion from KPa to atm:
1 KPa is equal to 0.00987 atm. To convert from KPa to atm we will multiply the given value with 0.00987 atm.
303.9 KPa × 0.00987 atm / 1 KPa
2.99 atm
Conversion from KPa to torr:
1 KPa is equal to the 7.5006 torr. To convert from KPa to torr we will multiply the KPa value by 7.5006.
303.9 KPa × 7.5006 torr/ 1 KPa
2279.43 torr
Conversion from KPa to psi:
psi is pound per square inch. 1 KPa is equal to the 0.1450 psi. To convert from KPa to psi we will multiply the KPa value by 0.1450 psi.
303.9 KPa × 0.1450 psi / 1 KPa
44.07 psi
Answer:
Explanation:
From the given information:
We are to make use of the spinach absorbance extract which is the corrected absorbance (y) = 0.306
And also the trendline equation:
y = 1609x + 0.0055
where,
x = absorbance of the spinach extract.
∴
0.306 = 1609x + 0.0055
collecting the like terms
0.306 - 0.0055 = 1609x
0.3005 = 1609x
x = 0.3005/1609
x = 1.8676 × 10⁻⁴
x ≅ 0.0002 M
No. of grams for the chlorophyll can be computed as follows:
recall that:
molar mass of chlorophyll = 893.5 g/mol
the volume = 25ml = (25/1000) L = 0.025 L
∴
In spinach solution, the no. of grams for the chlorophyll:
= (0.0002) mol/L × (893.5 g/mol) × (0.025) L
= 0.0044675 g
≅ 0.0045 g
In the spinach, the concentration of chlorophyll = no of grams of chlorophyll/ mass of the spinach
= 4.5 mg/0.1876 g
= 23.987 mg/g
≅ 24 mg/g
