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Keith_Richards [23]
2 years ago
11

Arrange the following elements in order of decreasing metallic character.

Chemistry
1 answer:
Ivenika [448]2 years ago
8 0

The arrangement of the elements in order of decreasing metallic character is: Rb, Zn, P, S, F, Ca, Co, Cr

<h3 /><h3>What are metals?</h3>

Metals are elements which are known by their special ability to form ions by a loss of electrons.

The increasing metallic character of metal is a measure of their ability to lose electrons.

Metallic character increases from right to left and down a group in the period table.

Metals are found to the left of the period table.

In conclusion, metals are known by their ability to lose electrons.

Learn more about metals at: brainly.com/question/25597694

#SPJ1

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Answer:

They are seperating

Explanation:

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EXPLAIN how to identify the reducing agent in a reaction of magnesium with oxygen
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Explanation:

Mg+O>MgO

Here the mg loses it electron and is oxidised and oxygen gains and is reduced.

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Mg is a reducing agent it makes oxygen to be reduced while itself being oxidised and vice versa.

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Calculate ΔG o for the following reaction at 25°C: 3Mg(s) + 2Al3+(aq) ⇌ 3Mg2+(aq) + 2Al(s) Enter your answer in scientific notat
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Answer:

-3.7771 × 10² kJ/mol

Explanation:

Let's consider the following equation.

3 Mg(s) + 2 Al³⁺(aq) ⇌ 3 Mg²⁺(aq) + 2 Al(s)

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

ΔG° = 3 mol × (-456.35 kJ/mol) + 2 mol × 0 kJ/mol - 3 mol × 0 kJ/mol - 2 mol × (-495.67 kJ/mol)

ΔG° = -377.71 kJ = -3.7771 × 10² kJ

This is the standard Gibbs free energy per mole of reaction.

5 0
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A element or compound which occurs naturally in the earth
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How many significant figures in 368.1371 ?
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